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ehidna [41]
3 years ago
11

How does a rubber rod become negativley charged trough friction/

Physics
2 answers:
iren2701 [21]3 years ago
7 0

Answer:

Hey

here's ur answer ⤵️

Explanation:

It touches a negatively charged object, and protons move off of the rod it is rubbed with another object and electrons move onto the rod.

It is rubbed with another object and protons move off of the rod.

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps </em>

natali 33 [55]3 years ago
3 0

Answer: Answer below hope it helps

Explanation: How does a rubber rod become negatively charged through friction? It touches a negatively charged object, and protons move off of the rod. ... It is rubbed with another object, and electrons move onto the rod. It is rubbed with another object, and protons move off of the rod.

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"State the process that divides one nucleus into two genetically identical nuclei"
kompoz [17]

Answer:

<em>Mitosis</em>

Explanation:

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Mitosis takes place during organism's growth, development, and asexual reproduction. in plants mitosis takes place in the terminal bud of the shoot at the tip of the roots and shoots. In animal mitosis occur at growth centres which are everywhere.

Mitosis produce diploid number, in order word, the number of chromosomes in each somatic cell of an organism is called the diploid number (2n)

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4 0
3 years ago
All of the following are regulated by the medulla except __________.
Lelechka [254]

Answer:

i think its B sorry if its wrong

7 0
3 years ago
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Humans evolved in Earth's atmosphere, therefore the pressures interior to the body are relatively close to atmospheric pressure.
harina [27]

Answer:

194516 sheets

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For the paper sheet to make the same effect as the atmospheric pressure P, then the gravity F from the paper sheet must be

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4 0
3 years ago
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Pweese help luvs qwq<br> pweese look at the image?
hjlf

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12 m/s

Explanation:

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6 0
3 years ago
A dust particle with mass of 5.4×10−2 g and a charge of 2.3×10−6 C is in a region of space where the potential is given by V(x)=
user100 [1]

Answer:

1.6 m/s^2

Explanation:

Hello!

To calculate the acceleration we must know the electric field. The electric field and the potential are related by:

E = -\frac{dV}{dx} =- 2.6(\frac{V}{m^{2}})x + 8.1(\frac{V}{m^{3}})x^{2}

If the particle starts at 2.3m, the electric field is:

E = 36.869 V/m = 36.869 N/C

So, the force on the particle is:

F = q E =  2.3×10^−6 C * 36.869 N/C = 8.48 x 10^-5 N

And its acceleration is :

a = F/m =  8.48 x 10^-5 N / 5.4×10−5 kg = 1.57 m/s^2

Rounded to two significant figures:

1.6 m/s^2

6 0
4 years ago
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