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2 years ago

. Một bình kín không dãn nở, chứa 14g nitơ ở 1atm và 27°C, được đung nóng làm áp suất tăng lên đến 5atm. Hãy xác định:

Physics

1 answer:

Aleonysh [2.5K]2 years ago

8 0

Answer:

t5 is a great place to work for and I am very excited about this opportunity and I look forward to working with you and I look

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What is an example of an organism that reproduces

RideAnS [48]

Sea anemones; Coral; Starfish; Some non-flowering plants. Strawberry; Onion; Potato. Mushrooms are an example<span> of asexually </span>reproducing organisms<span>.

hoped i helped my fellow brainily user</span>

4 0

3 years ago

The luxury liner Queen Elizabeth 2 has a diesel-electric powerplant with a maximum power of 90 MW at a cruising speed of 31.5 kn

AlexFokin [52]

Answer:

5558643.69 N

Explanation:

F = Force

v = Velocity = 31.5 knots

Converting to m/s

$1\ knot=0.514\ m/s$

$31.5\ knot=31.5\times 0.514\ m/s=16.191\ m/s$

Power is given by

$P=Fv\\\Rightarrow F=\frac{P}{v}\\\Rightarrow F=\frac{90\times 10^6}{16.191}\\\Rightarrow F=5558643.69\ N$

The forward force is exerted on the ship at this highest attainable speed is 5558643.69 N

5 0

3 years ago

A father pushes his child on a swing. He pushes with a force of 20 N or a distance of 1 m, with the force always maintained para

Firlakuza [10]

Answer:

20 Joules

Explanation:

Work is done whenever a force moves a body through a certain distance in the direction of the force. So, work done is the product of force and distance moved.

Therefore, we have;

Work done = Force x distance

i.e Wd = Fs

Given that: F = 20 N and s = 1 m, then;

Wd = 20 N x 1 m

= 20 Nm

The work done by the father is 20 Joules(Nm).

7 0

3 years ago

What is an object’s acceleration if it is moving at 30 m/s and comes to a stop in 5 s? –30 m/s2 –6 m/s2 30 m/s2 6 m/s2

Tanya [424]

Answer:32m/s

Explanation:

3 0

3 years ago

Read 2 more answers

In order to open the clam it catches, a seagull will drop the clam repeatedly onto a hard surface from high in the air until the

Vedmedyk [2.9K]

Answer:

2.2 s

Explanation:

Hi!

Let's consider the origin of the coordinate system at the ground, and consider that the clam starts with zero velocity, the equation of motion of the clam is given by

$x(t) = 23.1 m - \frac{1}{2}(9.8 m/s^2) t^2$

We are looking for a time t for which x(t) = 0

$0 = 23.1 m - (4.9 m/s^2) t^2$

Solving for t:

$t = \sqrt{\frac{23.1}{4.9}} s = 2.17124 s$

Rounding at the first decimal:

t = 2.2 s

4 0

3 years ago