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2 years ago

9

Please help me answer the question in the picture

2 answers:

Scilla [17]2 years ago

5 0

Answer:

B

Step-by-step explanation:

formula for equation of line with two given points:

(y-y1)= m(x-x1)

so Its B

Viefleur [7K]2 years ago

5 0

It’s B. You’re Welcome

You might be interested in

In the proportion 2:3 = 16:24 ,the product of the two middle values is __.

klio [65]

Answer:

48 and 48

Step-by-step explanation:

product means multiplication

two middle values are 3 and 16

3*16 = 48

two outside values are 2 and 24

2*24 = 48

4 0

2 years ago

What is the answer what is q

Brrunno [24]

Q is negative two thirds which is written as -2/3

8 0

2 years ago

Read 2 more answers

I know you want to answer this question.

Alik [6]

Answer:

D. x = 3

Step-by-step explanation:

$\frac{1}{2} ^{x-4}$ - 3 = $4^{x-3}$ - 2

First, convert $4^{x-3}$ to base 2:

$4^{x-3}$ = $(2^{2})^{x-3}$

$\frac{1}{2} ^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Next, convert $\frac{1}{2} ^{x-4}$ to base 2:

$\frac{1}{2} ^{x-4}$ = $(2^{-1})^{x-4}$

$(2^{-1})^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{-1})^{x-4}$ = $2^{-1*(x-4)}$

$2^{-1*(x-4)}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{2})^{x-3}$ = $2^{2(x-3)}$

$2^{-1*(x-4)}$ - 3 = $2^{2(x-3)}$ - 2

Apply exponent rule: $a^{b+c}$ = $a^{b}$ $a^{c}$ :

$2^{-1(x-4)}$ = $2^{-1x}$ * $2^{4}$ , $2^{2(x-3)}$ = $2^{2x}$ * $2^{-6}$

$2^{-1 * x}$ * $2^{4}$ - 3 = $2^{2x}$ * $2^{-6}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$2^{-1x}$ = $(2^{x})^{-1}$ , $2^{2x}$ = $(2^{x})^{2}$

$(2^{x})^{-1}$ * $2^{4}$ - 3 = $(2^{x})^{2}$ * $2^{-6}$ - 2

Rewrite the equation with $2^{x} = u$ :

$(u)^{-1}$ * $2^{4}$ - 3 = $(u)^{2}$ * $2^{-6}$ - 2

Solve $u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2:

$u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2

Refine:

$\frac{16}{u}$ - 3 = $\frac{1}{64}$ $u^{2}$ - 2

Add 3 to both sides:

$\frac{16}{u}$ - 3 + 3 = $\frac{1}{64}$ $u^{2}$ - 2 + 3

Simplify:

$\frac{16}{u}$ = $\frac{1}{64}$ $u^{2}$ + 1

Multiply by the Least Common Multiplier (64u):

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify:

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify $\frac{16}{u}$ * 64u:

1024

Simplify $\frac{1}{64}$ $u^{2}$ * 64u:

$u^{3}$

Substitute:

1024 = $u^{3}$ + 64u

Solve for u:

u = 8

Substitute back u = $2^{x}$ :

8 = $2^{x}$

Solve for x:

x = 3

4 0

3 years ago

If possible step by step explanation. thank you!

elixir [45]

Answer:

A

Step-by-step explanation:

$\frac{(3x^{2} )^\frac{1}{2} }{3^\frac{1}{2} } =3$

$(3x^2)^\frac{1}{2} = 3^\frac{1}{2} x$

Remember that $\frac{x^b}{x^c} =$ x^(b-c)

Using that $\frac{3^\frac{1}{2}x }{3^\frac{1}{2} }$ =3^(1/2x-1/2)=3^((x-1)/2)

$3^\frac{x-1}{2} =3^1$

So we can say: $\frac{x-1}{2} =1$ , because the bases are the same

We can multiply both sides of the equation by 2. We get x-1=2, and x=3. Which is A.

7 0

2 years ago

Help please. !!! Practical math

Neko [114]

Put all numbers in order from least to greatest
median is the middle number
so
5,9,10,11,12,14
median = ( 10+11)/2 = 10.5

answer
C. 10.5

3 0

3 years ago

Read 2 more answers