3 years ago

N2__+3H2= 2NH3

1 answer:

5 0

Use the molar mass of ammonia to change the grams to moles and then use mole-mole ratio

100. g NH3 (1 mol NH3/ 17.04 g) (3 mol H2/ 2 mol NH)= 8.80 moles H2

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What is the concentration of a potassium iodate solution after you complete the following porcedure? Pipette 10 mL of a 0.31 M p

zubka84 [21]

Given:

Initial concentration of potassium iodate (KIO3) M1 = 0.31 M

Initial volume of KIO3 (stock solution) V1 = 10 ml

Final volume of KIO3 V2 = 100 ml

To determine:

The final concentration of KIO3 i.e. M2

Explanation:

Use the relation-

M1V1 = M2V2

M2 = M1V1/V2 = 0.31 M * 10 ml/100 ml = 0.031 M

Ans: The concentration of KIO3 after dilution is 0.031 M

4 0

3 years ago

borishaifa [10]

M = 2 . 8 . 2

Valence Electron of M = 2

M ==> M⁺² + 2 e⁻

a. M⁺² + OH⁻ ==> M(OH)₂

b. M⁺² + PO₄⁻³ ==> M₃(PO₄)₂

7 0

3 years ago

For a tablet containing 500. mg of vitamin C, calculate how many ml of 0.095 M NaOH is required to reach the equivalence point.

Gala2k [10]

Answer:

mL of NaOH required =29.9mL

Explanation:

Let us calculate the moles of vitamin C in the tablet:

The molar mass of Vitamin C is 176.14 g/mole

$moles=\frac{mass}{molarmass}=\frac{500mg}{176.14}=\frac{0.5}{176.14}=0.0028$

Thus we need same number of moles of NaOH to reach the equivalence point.

For NaOH solution:

$moles=MolarityXvolume=0.095Xvolume$

$0.00283=0.095Xvolume$

$volume=0.0299L=29.9mL$

7 0

4 years ago

Quiz time!

kykrilka [37]

potassium belongs to group IA of the periodic table.

7 0

3 years ago

Read 2 more answers

Select all that apply.

cupoosta [38]

Answer:

B and C

Explanation:

I think the answer correct is C because you never know in what temperature the block of ice is going to melt but if it says select all that apply its possible that B might be useful.

7 0

2 years ago