3. What is the volume of a rectangular solid that is 40 centimeters long, 10 centimeters wide, and 5

Alex17521 [72]

Answer:

2 AsCl₃ + 3 H₂S → As₂S₃ + 6 HCl

Explanation:

When we balance a chemical equation, what we are trying to do is to achieve the same number of atoms for each element on both sides of the arrow. On the right of the arrow is where we can find the products, while the reactants are found on the left of the arrow.

We usually balance O and H atoms last.

AsCl₃ + H₂S → As₂S₃ +HCl

reactants

As --- 1

Cl --- 3

H --- 2

S --- 1

products

As --- 2

Cl --- 1

H --- 1

S --- 3

2 AsCl₃ + H₂S → As₂S₃ +HCl

reactants

As --- 2

Cl --- 6

H --- 2

S --- 1

products

As --- 2

Cl --- 1

H --- 1

S --- 3

The number of As atoms is now balanced.

2 AsCl₃ + 3 H₂S → As₂S₃ +HCl

reactants

As --- 2

Cl --- 6

H --- 6

S --- 3

products

As --- 2

Cl --- 1

H --- 1

S --- 3

The number of S atoms is now equal on both sides.

2 AsCl₃ + 3 H₂S → As₂S₃ + 6 HCl

reactants

As --- 2

Cl --- 6

H --- 6

S --- 3

products

As --- 2

Cl --- 6

H --- 6

S --- 3

The equation is now balanced.

3 0

3 years ago

What is the definition of DNA in meiosis

mario62 [17]

Like mitosis, meiosis is a form of eukaryotic cell division. However, these two processes distribute genetic material among the resulting daughter cells in very different ways. meiosis gives rise to four unique daughter cells, each of which has half the number of chromosomes as the parent cell. Because meiosis creates cells that are destined to become gametes (or reproductive cells), this reduction in chromosome number is critical — without it, the union of two gametes during fertilization would result in offspring with twice the normal number of chromosomes!

6 0

4 years ago

Write the name for the IONIC compound that contains two aluminum atoms and three sulfur atoms. (Need help ASAP)

Arada [10]

Ionic compound
Al +3 charge, Aluminum
S -2 charge, Sulfur

Al2S3

6 0

3 years ago

The density of a 20.3 m ch3oh (methanol) solution is 0.858 g/ml. what is the molality of this solution? h2o is the solvent.

aliina [53]

The difference of molarity and molality is in the units:

Molarity is expressed in mol solute / L solution;

while Molality is expressed in mol solute / kg solvent

Since no other data is given, let us assume that the contribution of methanol on the total volume is negligible. So that,

Molality = (20.3 mol / L) (1 L / 0.858 kg)

Molality = 23.66 m

The closest answer is letter C. 23.7 m

6 0

4 years ago

1. If there are 100 navy beans, 27 pinto beans and 173 blackeyed peas in a container, what is the percent abundance in the conta

kompoz [17]

The answers to the two questions are:

1. The percent abundance in the container which has 100 navy, 27 pinto, and 173 black-eyed peas beans is 33.3%, 9.0%, and 57.7% for navy bean, pinto bean, and black-eyed peas beans, respectively.

2. The weighted average score for the scores of 85, 75, 96 obtained from the evaluations of exams (20%), labs (75%), and homework (96%) is 84.1.

1. The percent abundance by type of bean is given by:

$\% = \frac{n}{n_{t}} \times 100$ (1)

Where:

n: is the number of each type of beans

$n_{t}$ : is the total number of beans

The total number of beans can be calculated by adding the number of all the types of beans:

$n_{t} = n_{n} + n_{p} + n_{b}$ (2)

Where:

$n_{n}$ : is the number of navy beans = 100

$n_{p}$ : is the number of pinto beans = 27

$n_{b}$ : is the number of black-eyed peas beans = 173

Hence, the total number of beans is (eq 2):

$n_{t} = 100 + 27 + 173 = 300$

Now, the percent abundance by type of bean is (eq 1):

Navy beans

$\%_{n} = \frac{100}{300} \times 100 = 33.3 \%$

Pinto beans

$\%_{p} = \frac{27}{300} \times 100 = 9.0 \%$

Black-eyed peas beans

$\%_{b} = \frac{173}{300} \times 100 = 57.7 \%$

Hence, the percent abundance by type of bean is 33.3%, 9.0%, and 57.7% for navy bean, pinto bean, and black-eyed peas beans, respectively.

2. The average score (S) can be calculated as follows:

$S = e*\%_{e} + l*\%_{l} + h*\%_{h}$ (3)

Where:

e: is the score for exams = 85

l: is the score for lab reports = 75

h: is the score for homework = 96

$%_{e}$ $\%_{e}$ : is the percent for exams = 70.0%

$\%_{l}$ : is the percent for lab reports = 20.0%

$\%_{h}$ : is the percent for homework = 10.0%

Then, the average score is:

$S = 85*0.70 + 75*0.20 + 96*0.10 = 84.1$

We can see that if the score for each evaluation is 100, after multiplying every evaluation for its respective percent, the final average score would be 100.

Therefore, the weighted average score will be 84.1.

Find more about percents here:

brainly.com/question/255442?referrer=searchResults

brainly.com/question/22444616?referrer=searchResults

I hope it helps you!

4 0

3 years ago