The force vector that has a magnitude of 12.0 N. and is oriented 60° to the left of the (y) has the followings components:
To solve this exercise the formulas and procedures we will use are:
- v(x) = v * cosine (angle)
- v(y) = v * sine (angle).
Where:
- v= magnitude of the vector
- v(x) = component of the vector on the (x) axis
- v(y) = component of the vector on the (y) axis
- angle = angle
Information about the problem:
- angle = 60º
- v = 12.0 N
- v(x)= ?
- v(y)= ?
Applying the formula of the component of the vector in the (x) axis we have:
v(x) = v * cosine (angle).
v(x) = 12.0 N * cosine (60º)
v(x) =6 N
Applying the formula of the component of the vector in the (y) axis we have:
v(y) = v * sine (angle)
v(y) = 12.0 N * sine (60º)
v(y) = 10.39 N
<h3>What is a vector?</h3>
It can be said to be a straight line described by a point (a) and (b) that has direction and sense.
Learn more about vector at: brainly.com/question/2094736
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Winds are immigrants. They're named for where they have already been and are coming from, not for where they're going.
A Westerly wind is coming from the West. Anything caught in it is being blown toward the east.
The answer is the third one. Maglev is short for Magnetic Levitation in which trains skim on a guideway utilizing the guideline of attractive shock. Every magnet has two shafts. Presently in the event that you play with two magnets, you'll understand that inverse shafts pull in, though comparable posts repulse. This shocking property of magnets is utilized as a part of Maglev trains. However,instead of utilizing lasting magnets, the standard of electromagnetism is utilized to make solid and huge impermanent magnets. At the point when an electric current is gone through a loop of wire, attractive field is created around the curl as indicated by Faraday's laws.
I’m pretty sure c I had this awhile ago but not sure
Answer:
s₁ = 240,000 km
Explanation:
The distance between both the focuses f₁ and f₂ will be the sum of distances of the moon from each focus at a given point. Therefore,
s = s₁ + s₂
where,
s = total distance between the focuses = ?
s₁ = distance between f1 and moon = 200,000 km
s₂ = distance between f₂ and moon = 300,000 km
Therefore,
s = 200,000 km + 300,000 km
s = 500,000 km
Now, when the distance from f₂ becomes 260,000 km, then the distance from f₁(planet) will become:
s = s₁ + s₂
500,000 km = s₁ + 260,000 km
s₁ = 500,000 km - 260,000 km
<u>s₁ = 240,000 km</u>
