Answer:
3.65 g / ml correct to 3 sig. fig.
Explanation:
The computation of the concentration required is shown below:
As we know that
[A] = mass of solute ÷ volume of solution
Before that first find the mass of solute
Given that
Initial weight = 5.55g
And,
Final weight = 92.7 g
So,
Mass of KCl is
= 92.7 - 5.55
= 87.15 g ~ 87.2 g
Now the KCi is fully dissolved, so the volume is 23.9 ml
So, concentration is
= 87.2 g ÷ 23.9 ml
= 3.65 g / ml correct to 3 sig. fig.
2SO₂ + O₂ = 2SO₃
n(O₂)=1 mol
n(SO₂)=2n(O₂)
n(SO₂)=2 mol
Water is formed when this happens
C + O2= CO2
CO2 is limit
5.4-3.72= 1.68 g of C is excess
5.4 g = 100%
3.72 g = x
x=68.9 %
Answer:
A. Electrolyte
Explanation:
Concentrated sulfuric acid has a density of 1.84 g/millimeter. When you dilute this with water to 5.20 M, you then have a density of 1.30 g/millimeter, which then can be used as a lead storage for batteries in automobiles. (Got help to answer this at Www.wyzant.com
