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Answer:
a) 0.040625 m
b) 5.02272 J
Explanation:
k = Spring constant
x = Stretched length
F = Force
a)
Extension of the spring would be 0.040625 m
b) Work done in a spring
The work done by the shopper to stretch this spring a total distance of 8.00 cm is 5.02272 J
Answer:
F = 1.68 N
Explanation:
Let's solve this exercise in parts.
Let's use the concept of conservation of the mechanical nerve
initial
Em₀ = 500 J
The energy is totally kinetic
Em₀ = K = ½ m v₀²
v₀ =
v₀ = √ (2 500/32)
v₀ = 5.59 m / s
now with kinematics we can find a space
v² = v₀² - 2 a x
the negative sign is because the body is stopping
a =
let's calculate
a = (5.59² - 5.1²) / 2 50
a = 0.0524 m / s²
Finally let's use Newton's second law
F = ma
F = 32 0.0524
F = 1.68 N
So what you do is you use the formula shown below:
specific heat capacity = energy required / (mass * change in temperature)
here ,
energy required = 10.0°C Note that cal. is short form for °C
mass (m) = 3.1g
change in temperature (ΔT) = 17.9°C Note that "ΔT" means change in temperature
So, plugging the values into the formula, we get,
Specific heat capacity=
=
= 0.1802 cal./g°C <span>i rounded the answer to the fourth decimal point
</span>
specific heat capacity = energy required / (mass * change in temperature)
here ,
energy required = 10.0°C Note that cal. is short form for °C
mass (m) = 3.1g
change in temperature (ΔT) = 17.9°C Note that "ΔT" means change in temperature
So, plugging the values into the formula, we get,
Specific heat capacity=
=
= 0.1802 cal./g°C <span>i rounded the answer to the fourth decimal point
</span>
Answer:
Explanation:
The source is approaching the observer which is moving away from the source , so applying Doppler's effect
where n is apparent frequency , n₀ is original frequency , V₀ is velocity of observer , V_S is velocity of source , V is velocity of sound
Putting the given values
=
= 536
So apparent frequency will be same as original frequency .
ie 536 .