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Allisa [31]
3 years ago
11

Determine the mass of 4.20 moles of C6H12

Chemistry
1 answer:
Sergeu [11.5K]3 years ago
6 0

Explanation:

Hope this help sweetiee

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How did oxygen (O2) get into Earth's atmosphere? How did oxygen (O2) get into Earth's atmosphere? It was captured from the solar
Ugo [173]

Answer:

Option (4)

Explanation:

The primitive atmosphere was comprised of lesser or no amount of oxygen. With the progressive time, primitive organisms appeared such as the primitive aquatic plants, algae, and cyanobacteria, that carried out the process of photosynthesis in the presence of sunlight, water, and CO₂, and in return produced the food and oxygen. This is how the rapid photosynthesis process led to the increasing amount of oxygen in the atmosphere that facilitates the growth and evolution of different life forms on earth.

Thus, the correct answer is option (4).

3 0
3 years ago
What is the main difference between the Bohr model and the electron cloud model of the atom.
leonid [27]
Electron cloud is an informal term in physics. It is used to describe where electrons are when they go around the nucleus of an atom. The electron cloud model is different from the older Bohr atomic modelby Niels Bohr. Bohr talked about electrons orbiting the nucleus.
8 0
4 years ago
Read 2 more answers
Se tiene una solución acuosa 2M de carbonato de potasio. Expresar su concentración en %p/v y Normalidad.
zepelin [54]

Answer:

Normalidad = 4N

%p/V = 27.6%

Explanation:

La solución 2M de carbonato de potasio contiene 2moles de carbonato por litro de solución. La normalidad son los equivalente de carbonato de potasio (2eq/mol) por litro de solución:

2moles * (2eq/mol) = 4eq / 1L = 4N

El porcentaje peso volumen es el peso de carbonato en gramos dividido en el volumen en mL por 100:

%p/V:

Masa K2CO3 -Masa molar: 138.205g/mol-

2moles * (138.205g/mol) = 276g K2CO3

Volumen:

1L * (1000mL/1L) = 1000mL

%p/V:

276g K2CO3 / 1000mL * 100

<h3>%p/V = 27.6%</h3>
6 0
3 years ago
Nitroglycerin, used both in medicine and as an explosive, can be prepared by the carefully controlled reaction of glycerol (C3H8
vesna_86 [32]

The mass of nitric acid (HNO₃) required for the production of 2.8 g of nitroglycerin? (C₃H₅N₃O₉) is 2.33 g

We'll begin by calculating the mass of HNO₃ that reacted and the mass of C₃H₅N₃O₉ produced from the balanced equation. This can be obtained as follow:

C₃H₈O₃ + 3HNO₃ —> C₃H₅N₃O₉ + 3H₂O

Molar mass of HNO₃ = 1 + 14 + (16×3)

= 1 + 14 + 48

= 63 g/mol

Mass of HNO₃ from the balanced equation = 3 × 63 = 189 g

Molar mass of C₃H₅N₃O₉ = (12×3) + (1×5) + (14×3) + (16 × 9)

= 36 + 5 + 42 + 144

= 227 g/mol

Mass of C₃H₅N₃O₉ from the balanced equation = 1 × 227 = 227 g

<h3>SUMMARY:</h3>

From the balanced equation above,

227 g of C₃H₅N₃O₉ were produced by 189 g of HNO₃.

Finally, we shall determine the mass of HNO₃ that will produce 2.8 g of C₃H₅N₃O₉. This can be obtained as follow:

From the balanced equation above,

227 g of C₃H₅N₃O₉ were produced by 189 g of HNO₃.

Therefore,

2.8 g of C₃H₅N₃O₉ will be produce by = \frac{2.8 * 189}{227} \\\\ = 2.33 g of HNO₃

Thus, the mass of nitric acid (HNO₃) required for the production of 2.8 g of nitroglycerin? (C₃H₅N₃O₉) is 2.33 g

Learn more: brainly.com/question/24918379

3 0
3 years ago
sometimes it's hard to tell if the bowl-shaped feature at the top of a volcano is a crater or a caldera. you can usually determi
Stells [14]

Answer:

By finding if the volcano type is active or extinct.

Explanation:

A vent for the molten rock to move out on to the surface of the Earth is known as a crater. On the other hand, the outcome of a huge volcanic eruption that emits a large volume of magma leaving behind a large opening in the ground is known as a caldera.  

The formation of calderas takes place when the large chamber of magma gets vacant by the subsurface movement of the magma or by a volcanic eruption. The rock, which forms the roof of the magma chamber that has no support then get collapsed to produce a big crater.  

4 0
4 years ago
Read 2 more answers
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