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3 years ago

Glucose, C6H12O6, is used as an energy source by the human body. The overall reaction in the body is described by the equation:

Chemistry

1 answer:

umka2103 [35]3 years ago

8 0

Answer:

1) $m_{O_2}=24.5gO_2$

2) $m_{CO_2}=33.7gCO_2$

Explanation:

Hello,

1) In this case, by considering the given reaction, starting by 23.0 g of glucose, the grams of oxygen by stoichiometry result:

$m_{O_2}=23.0gC_6H_{12}O_6*\frac{1molC_6H_{12}O_6}{180gC_6H_{12}O_6}*\frac{6molO_2}{1molC_6H_{12}O_6}*\frac{32gO_2}{1molO_2} \\m_{O_2}=24.5gO_2$

2), Now, by means of also stoichiometry, the grams of carbon dioxide that are produced result:

$m_{CO_2}=23.0gC_6H_{12}O_6*\frac{1molC_6H_{12}O_6}{180gC_6H_{12}O_6}*\frac{6molCO_2}{1molC_6H_{12}O_6}*\frac{44gCO_2}{1molCO_2}\\m_{CO_2}=33.7gCO_2$

Best regards.

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t physiological pH, the carboxylic acid group of an amino acid will be ________, while the amino group will be ________, yieldin

astraxan [27]

Answer:

At physiological pH,the carboxylic acid group of an amino acid will be deprotonated while the amino group will be protonated,yielding the zwitter ion form.

Explanation:

Deprotonated means removal of protons in an acid base reaction and protonated means addition of protons in an acid base reaction.

Both protonated and de protonated reaction takes place in catalytic acid bade reaction by changing either it's mass or it's charge.

During formation of zwitter ion, the carboxylic acid will be deprotonated by donating the H+ ion while the amino acid is protonated by taking the H+ ion.

R-CH-COOH R-CH-COO-

I ⇒ I

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3 years ago

1. A student tried to solve the following problem by selecting the tile as shown. What, if anything, did the student do wrong?

slega [8]

Answer:

B. The student chose the correct tile, but needs to flip the tile to make the units cancel

Explanation:

Based on the reaction:

2AgNO₃(aq) + Cu(s) → 2Ag(s) + Cu(NO₃)₂ (aq)

2 moles of AgNO₃ react per mole of Cu producing 2 moles of Ag and 1 mole of Cu(NO₃)₂

Thus, if you want to produce 6.75moles of Cu(NO₃)₂ you need:

$6.75moles of Cu(NO_3)_2 \frac{2 mol AgNO_3 }{1 mol Cu(NO_3)_2}$ = 13.50 moles of AgNO₃ are needed

Thus, if you analize the tile shown by the student:

B. The student chose the correct tile, but needs to flip the tile to make the units cancel

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3 years ago

Mature elephants consume an average of 600 pounds of food per day. If an elephant

MAXImum [283]

Answer:

$\large \boxed{\text{4 600 000 kg or 4600 Mg}}$

Explanation:

1. Calculate the adult life

If the elephant is an adult from its 10th birthday until the day before its 56th birthday, its

Adult life = 55 - 10 + 1 = 46 yr

2. Convert years to days

$\text{Adult life} = \text{46 yr} \times \dfrac{\text{365.25 da}}{\text{1 yr}} = \text{16 800 da}$

3. Convert days to pounds of feed

$\text{Feed} = \text{16 800 da} \times \dfrac{\text{600 lb}}{\text{1 da}} = 1.01 \times 10^{7} \text{ lb}$

4. Convert pounds to kilograms and megagrams

$\text{Feed} =1.01 \times 10^{7} \text{ lb} \times \dfrac{\text{1 kg}}{\text{2.20 lb}} =\textbf{4 600 000 kg} = \textbf{4600 Mg}\\\\\text{The elephant will eat $\large \boxed{\textbf{4 600 000 kg or 4600 Mg}}$ of food.}$

Note: The answer can have only two significant figures because that is all you gave for age of the elephant.

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3 years ago

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RideAnS [48]

Answer:

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2 years ago

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Inessa05 [86]

Answer: sulfer

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3 years ago