All categories

2 years ago

If a 50kg man climed a 5m ladder on the moon how much would the gpe be on earth

Physics

1 answer:

Crazy boy [7]2 years ago

5 0

Explanation:

Since, the gravity in moon is 1/6th that of earth.

Therefore,

5m ladder if climed on moon will be equal to 1/6th that on earth .i.e 5×1/6=0.83m

You might be interested in

What is an non-example of a switch

loris [4]

Dont really understand what youre asking but switches can be used to turn things on and off.

3 0

3 years ago

To be effective, an exercise program must be?

ExtremeBDS [4]

To be effective, an exercise program must have an aerobic form, portion for strength enhancement, and a stretching part. These three things are essential because they each target specific improvements in your body. For example, aerobics can help you maintain your body’s fitness or make it better. This usually targets your heart rate and ensures that you burn fat while doing so. Second is strength enhancement; this will make sure that your body becomes better – not just in a feeble state. Lastly is stretching, your muscles are like rubber bands. You cannot end or start your exercise program without stretching simply because they can damage your muscles as well. Aside from this, stretching can stop you from shocking your body into a physical activity, which may cause you to lose consciousness or have undue stress and fatigue.

3 0

3 years ago

Read 2 more answers

Police radar equipment is used to detect the speed of objects. In one trial, the radar equipment records a stationary tree as tr

Brut [27]

Answer:

reliability

accuracy

Explanation:

If a reading of a measurement is consistently the same then the measurement is reliable.

If a reading of measurement is close the actual value of the measurement then the reading is accurate.

Here, a stationary tree shows reading 6 mph once and 0 mph another instant. So, neither the reading of a measurement is consistent not the reading of measurement is close the actual value.

Hence, the radar has problems in its reliability and accuracy

8 0

3 years ago

A constant force is applied to an object, causing the object to accelerate at 10 m/s^2. What will the acceleration be if: a) The

Liula [17]

What you need to know is that the force is

F=ma

The force is the product of mass and acceleration

this means that the acceleration is

a=F/m

a) The force is halved?
this means that f will be $\frac{F}{2}$ now:

a= $\frac{F}{2m}$

So the accelaration will also he halved (it's the original acceleratation divided by 2)

b) The object's mass is halved?
a= $\frac{F}{m/2}$ =a= $\frac{F2}{m}$

which is the original acceleration times two!! so it will double

c) The force and the object's mass are both halved?
now we have

a= $\frac{F/2}{m/2}$ =a= $\frac{2F}{2m}$ =a= $\frac{F}{m}$

so they will cancel each other out and the acceleration will stay the same!

5 0

2 years ago

ivann1987 [24]

Answer:

Required energy Q = 231 J

Explanation:

Given:

Specific heat of copper C = 0.385 J/g°C

Mass m = 20 g

ΔT = (50 - 20)°C = 30 °C

Find:

Required energy

Computation:

Q = mCΔT

Q = 20(0.385)(30)

Required energy Q = 231 J

4 0

3 years ago