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stiv31 [10]
2 years ago
11

A collection of pennies was investigated. 10.00% were found to have been minted in San Francisco with an average mass of 2.15 g

and 90.00% we’re minted in in Philly with an average mass of 2.156 g. What was the average mass of pennies in this sample? Give the correct answer with the proper amount of significant figures
Chemistry
1 answer:
german2 years ago
5 0

The average mass of the pennies in the sample is 2.16 g.

We have a set of pennies from which 10.00% have an average mass of 2.15 g and 90.00% have an average mass of 2.156 g. The average mass (am) of the whole set is a weighted average, that considers the mass (m) and the percentage (perc) of each group. We can calculate it using the following expression.

am=\frac{\Sigma m \times perc  }{100 \%} = \frac{2.15g \times 10.00\% + 2.156 g \times 90.00\% }{100\%} = 2.1554 g \approx 2.16 g

The average mass of the pennies in the sample is 2.16 g.

You can learn more about weighted average here: brainly.com/question/18554478

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II. sulfur (S) and carbon (C)

and

III. fluorine (F) and oxygen (O)

will form covalent bonds, so the answer will be:

e. II and III

Explanation:

To know is what type of bond is formed between atoms we need to look at the electronegativity difference between the atoms.

If the electronegativity difference is less than 0.4 there is a nonpolar covalent bond.

If the electronegativity difference is between 0.4 and 1.8 there is a polar covalent bond. (if is a metal involved we consider the bond to be ionic)

If the electronegativity difference is greater then 1.8 there is an ionic bond.

We have the following cases:

I. lithium (Li) and sulfur (S)

electronegativity difference = 2.5 (S) - 1 (Li) = 1.5 but because there is a metal involved the bond will be ionic

II. sulfur (S) and carbon (C)

electronegativity difference = 2.5 (S) - 2.5 (C) = 0 so the bond will be nonpolar covalent

III. fluorine (F) and oxygen (O)

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Learn more about:

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