The Earth rotates due to the manner in which it was formed. Earth began its rotation from the spinning movement of the accretion disk. In short, the earth rotates because of angular momentum caused by the accretion disk.
An athlete produced 840 watts of power in 0.6 seconds. And will produce 504 joule of work did this individual perform during the exercise.
<u>Solution:</u>
we know that power is the work done completed in a given interval of time.
Power = 
also, Work = Power × Time
Work = 840 × 0.6 = 504 joule
What is Power?
- The quantity of work that can be accomplished in a certain amount of time is measured by power.
- Power is expressed in joules per second (J/s) this is because work is denoted by the symbol J and time by the symbol s.
- This is the watt, which is also known as the power unit in SI (W). One joule of labor per second is equal to one watt.
- The number of watts that a device uses is indicated on labels for lightbulbs and other small appliances like microwaves.
- A force must be applied in order for work to be completed, and there must also be motion or displacement in the force's direction.
- The amount of force multiplied by the distance moved in the force's direction is known as the work done by a force acting on an item. Work has no direction and only magnitude. Work is a scalar quantity as a result.
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Answer:
t_1 = 0.5*pi*sqrt( m / k )
Explanation:
Given:
- The block of mass m undergoes simple harmonic motion. With the displacement of x from mean position is given by:
x(t) = A*cos(w*t)
Find:
- At what time t1 does the block come back to its original equilibrium position (x=0) for the first time?
Solution:
- The first time the block moves from maximum position to its mean position constitutes of 1/4 th of one complete cycle. So, the required time t_1 is:
t_1 = 0.25*T
- Where, T : Time period of SHM.
- The time period for SHM is given by:
T = 2*pi*sqrt ( m / k )
Hence,
t_1 = 0.25 * 2 * pi * sqrt( m / k )
t_1 = 0.5*pi * sqrt( m / k )
Answer:
i dont know i am right but here Luminous intensity is defined as dI=dΨλ / dΩ, where dΨλ is the luminous flux (light energy flux in watts per m2) emitted within a solid angle dΩ. The light energy flux may be expressed in terms of the incident x-ray energy flux and the x-ray absorption and conversion properties of the scintillator(7,8,9).
Explanation: