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romanna [79]
2 years ago
13

How many significant figures should be written in the sum 4.65g +9.032g+580.0078+540.439g?

Physics
1 answer:
Ne4ueva [31]2 years ago
7 0

Answer: 1.13 X 10^3 g or 1130 g

Explanation: When you add up everything, you will get 1134.1288 g = 1.11341218 X 10^3. But while adding significant figures, we always look for the least significant figures (here 4.65 has least sig. figures  i.e. 3) and take that as a reference to how many significant figures we should have in the answer. (Pretty hard to explain!) Hope you got it!!

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Where an electric field line crosses an equipotential surface, the angle between the field line and the equipotential is
n200080 [17]

Answer:

90 degree

Explanation:

Electric field line is vertical to the electric field line.

4 0
2 years ago
Please help me answer this question I will be given the brainliest as well
Sophie [7]

draw a horizontal straight line from 25 to 75 and connects the line drawn at 75 to the bottom of the graph (0) at 90 with a straight line

3 0
3 years ago
What is the energy of a photon of blue light with a wavelength of 460 nm?
kaheart [24]

Answer: E=4.321(10)^{-19} J

Explanation:

The energy E of a photon is given by:

E=h\nu (1)

Where:

h=6.626(10)^{-34}\frac{m^{2}kg}{s} is the Planck constant

\nu is the frequency light

On the other hand, there is an inverse relationship between \nu  and the wavelength \lambda:

\nu=\frac{c}{\lambda} (2)

Where:

c=3(10)^{8} m/s is the speed of light

\lambda=460 nm=460(10)^{-9}m is the wavelength

Substituting (2) in (1):

E=\frac{hc}{\lambda} (3)

E=\frac{(6.626(10)^{-34}\frac{m^{2}kg}{s})(3(10)^{8} m/s)}{460(10)^{-9}m}

Finally:

E=4.321(10)^{-19} J This is the energy of a photon of blue light, in Joules.

4 0
2 years ago
A person in a kayak starts paddling, and it accelerates from 0 to 0.65 m/s in a distance of 0.40 m. If the combined mass of the
SCORPION-xisa [38]

Answer:

Magnitude of the net force acting on the kayak = 39.61 N

Explanation:

Considering motion of kayak:-

Initial velocity, u =  0 m/s

Distance , s = 0.40 m

Final velocity, v = 0.65 m/s

We have equation of motion v² = u² + 2as

Substituting

   v² = u² + 2as

    0.65² = 0² + 2 x a x 0.4

    a = 0.53 m/s²

We have force, F  = ma

Mass, m = 75 kg

    F  = ma = 75 x 0.53 = 39.61 N

Magnitude of the net force acting on the kayak = 39.61 N

6 0
3 years ago
Find the impulse a 1500 kg car experiences slowing down from 40m/s to 10m/s?
Kitty [74]

Answer: - 45000 N.s

Explanation: Impulse is equal to the change in momentum

J = Δp

To solve for impulse we calculate the change in momentum

Δp = m ( Δv)

     = 1500 kg ( 10 m/s - 40 m/s)

     = - 45000 N.s

6 0
3 years ago
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