Question

PCl5(g) ⇋ PCl3(g) + Cl2(g)

Answer 1

Answer: The total pressure in the container is 2.00 atm

Explanation:

We are given:

Initial pressure of $PCl_5$ = 1.00 atm

For the given chemical equation:

$PCl_5(g)\rightleftharpoons PCl_3(g)+Cl_2(g)$

After the completion of reaction:

Pressure of $PCl_3$ = 1.00 atm

Pressure of $Cl_2$ = 1.00 atm

Total pressure of the container = $p_{PCl_3}+p_{Cl_2}=[1.00+1.00]=2.00atm$

Hence, the total pressure in the container is 2.00 atm

Answer 2

Answer:

The total pressure in the container is 2 atm (Option B)

Explanation:

Step 1: Data given

The initial pressure of the PCl5(g) is 1.00 atm

Volume of the container = 1.00 L

Step 2: The balanced equation

PCl5(g) ⇋ PCl3(g) + Cl2(g)

Step 3: Calculate the total pressure in the container

1mol of ideal gas has a pressure of 1 atm

If 1 mol of PCl5 completely decomposes into 1 mol PCl3 and 1 mol Cl2

Then the pressure for 1 mol PCl3 and 1 mol Cl2 is for both  1 atm

The total pressure would be 2*1 atm = 2 atm

The total pressure in the container is 2 atm