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2 years ago

To avoid using the variable "a"

Physics

1 answer:

sdas [7]2 years ago

6 0

Answer:

option c .

Explanation:

..............................

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1. What is technology?<br>techndegy

Naya [18.7K]

Answer:

the application of scientific knowledge for practical purposes, especially in industry. Another answer:the sum of techniques,skills,methods and processes used in the production of goods or services or in the accomplishment of objectives, such as scientific investigation

6 0

3 years ago

Chapter 36, Problem 007 Light of wavelength 586 nm is incident on a narrow slit. The angle between the first diffraction minimum

svp [43]

Answer:

$d =4.77\times 10^{-5}\ m$

Explanation:

given

wavelength of light λ = 479 nm

= 479 x 10⁻⁹ m

the angle

θ = 1.15 / 2 = 0.575°

using

condition for diffraction minimum ,

d sinθ = m λ

for first minimum m = 1

d sinθ = λ

therefore ,

slit width

$d =\dfrac{\lambda}{sin\theta}$

$d =\dfrac{479\times 10^{-9}}{sin 0.575^0}$

$d =\dfrac{479\times 10^{-9}}{0.01}$

$d =4.77\times 10^{-5}\ m$

hence, the width of the slit is equal to $d =4.77\times 10^{-5}\ m$

3 0

2 years ago

Plz help me with this activity :(

Marrrta [24]

As mass increases, the potential energy also increases, I hope that helped :)

8 0

2 years ago

Some element can be either solid or liquid. At the melting point, the liquid has 8 × 10-22 J more enthalpy per atom than the sol

OlgaM077 [116]

Answer:

481.76 J/mol

133.33 K

Explanation:

$N_A$ = Avogadro's number = $6.022\times 10^{23}$

Change in enthalpy is given by

$\Delta H=8\times 10^{-22}\times 6.022\times 10^{23}\\\Rightarrow \Delta H=481.76\ J/mol$

Entropy is given by

$\Delta S=6\times 10^{-24}\times 6.022\times 10^{23}\\\Rightarrow \Delta S=3.6132\ J/mol K$

Latent heat of fusion is given by

$L_f=\Delta H\\\Rightarrow L_f=481.76\ J/mol$

The latent heat of fusion is 481.76 J/mol

Melting point is given by

$T_m=\dfrac{L_f}{\Delta S}\\\Rightarrow T_m=\dfrac{8\times 10^{-22}\times 6.022\times 10^{23}}{6\times 10^{-24}\times 6.022\times 10^{23}}\\\Rightarrow T_f=133.33\ K$

Melting occurs at 133.33 K

3 0

2 years ago

Neutral substances have a pH of _____.

Alinara [238K]

Explanation:

Substances become neutral at the number 7 because at this point, the acid and Base are equal and becomes neutralized

4 0

2 years ago