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3 years ago

What energy transformations occur when a person turns on a lightbulb by connecting its

Physics

1 answer:

Irina18 [472]3 years ago

5 0

Answer:

Chemical energy to Electrical energy to Light energy

Explanation:

Chemical energy; This is the energy stored in the battery.
Electrical energy; This is the energy transformed by the battery and sent through the connecting wires to the lightbulb
Light energy; When the electrical energy gets to the light bulb ,the light bulb converts it to light energy. Which is seen when the light bulb is turned on.

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in a region where the electric field is uniform and points in the x direction, the electric potential is -2000 v at x = 8 m and

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3 years ago

suppose that you’re running a boy away from your dog who sits and watches you leave if you use the bicycle as a reference frame

solong [7]

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If you use the bicycle as a reference frame, your dog will appear to be moving backwards farther from you/your bicycle. Although the dog is sitting on one place, your bicycle is moving away from the dog

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4 years ago

Fluid flows at 2.0 m/s through a pipe of diameter 3.0 cm. What is the volume flow rate of the fluid in m^3/

fenix001 [56]

Answer:

Volume flow rate = $1.41 \times 10^{-3}m^3/s$

Explanation:

The volume flow rate through a channel can be gotten by multiplying its area and its velocity.

The channel under consideration is a circular channel. Hence, the cross-sectional area can be calculated by using the relation for calculating the area of a circle

Cross-sectional area = $\pi \times d^{2}/4$

$A = \pi \times (3\times 10^-2)^2 /4 = 7.07 \times 10 ^-4 m^2$

volume flow rate= $A = 7.07 \times 10 ^-4 m^2 X 2.0 = 1.41 \times 10^{-3}m^3/s$

Volume flow rate = $1.41 \times 10^{-3}m^3/s$

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4 years ago

In 3 seconds a car moving in a straight line increases its speed from 22.4 m/s to 29.1 m/s while a truck increases its speed fro

ANTONII [103]

Is there a picture?

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3 years ago

Two balls with equal masses, m, and equal speed, v, engage in a head on elastic collision. what is the final velocity of each ba

Allushta [10]

The collision is elastic. This means that both momentum and kinetic energy are conserved after the collision.

- Let's start with conservation of momentum. The initial momentum of the total system is the sum of the momenta of the two balls, but we should put a negative sign in front of the velocity of the second ball, because it travels in the opposite direction of ball 1. So ball 1 has mass m and speed v, while ball 2 has mass m and speed -v:
$p_i = p_1-p_2 = mv-mv =0$
So, the final momentum must be zero as well:
$p_f = 0$
Calling v1 and v2 the velocities of the two balls after the collision, the final momentum can be written as
$p_f = mv_1 + mv_2 = 0$
From which
$v_1 = -v_2$

- So now let's apply conservation of kinetic energy. The kinetic energy of each ball is $\frac{1}{2} mv^2$ . Therefore, the total kinetic energy before the collision is
$K_i = \frac{1}{2} mv^2 + \frac{1}{2} mv^2 = mv^2$
the kinetic energy after the collision must be conserved, and therefore must be equal to this value:
$K_f = K_i = mv^2$ (1)
But the final kinetic energy, Kf, is also
$K_f = \frac{1}{2} mv_1^2 + \frac{1}{2}mv_2^2$
Substituting $v_1 = -v_2$ as we found in the conservation of momentum, this becomes
$K_f = mv_2 ^2$
we also said that Kf must be equal to the initial kinetic energy (1), therefore we can write
$mv_2^2 = mv^2$

Therefore, the two final speeds of the balls are
$v_2 = v$
$v_1 = -v_2 = -v$

This means that after the collision, the two balls have same velocity v, but they go in the opposite direction with respect to their original direction.

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3 years ago