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alukav5142 [94]
3 years ago
10

Helppppppppppppppppppppp

Chemistry
1 answer:
icang [17]3 years ago
4 0

Answer:

A car battery discharging

Explanation:

there is no chemical reaction happening

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What is the total mass of KNO3 that must be dissolved in 50. grams of H2O at 60.°C to make a saturated solution?
IRINA_888 [86]

at 60ºC:

106 g KNO₃ -------------- 100 g (H₂O)
? g KNO₃ ------------------ 50.0 g (H₂O)

mass KNO₃ = 50.0 * 106 / 100

mass KNO₃ = 5300 / 100

<span>= </span>53 g of KNO₃

answer (2)

<span>hope this helps!</span>

4 0
4 years ago
Read 2 more answers
There are three stable isotopes of magnesium. Their masses are 23.9850, 24.9858, and 25.9826 u. If the average atomic mass of ma
olganol [36]

Answer:

²⁵ Mg = 10.00%

²⁶ Mg = 11.0%

Explanation:

Given that:

Magnesium ²⁴Mg has an abundance of 78.99%

Hence, (100 - 78.99)% = 21.01%

21.01% is the abundance of ²⁵ Mg and ²⁶ Mg

Suppose,

²⁵ Mg = x

²⁶ Mg = (21.01 - x)%

Then;

avg. atomic mass = \dfrac{78.99}{100 }(23.9850)+\dfrac{x}{100}(24.9858) +\dfrac{21.01-x}{100}(25.9826)

where the avg. atomic mass = 24.3050

∴

24.3050 \times 100 = {78.99}(23.9850)+\dfrac{x}{100}(24.9858) +\dfrac{21.01-x}{100}(25.9826)

2430.5 = 2440.46915 -0.9968 x

0.9968x = 2440.46915 - 2430.5

0.9968x = 9.96915

x  =  9.96915/0.9968

x  =  10.00%

∴ Recall that:

²⁵ Mg = x

²⁶ Mg = (21.01 - x)%

²⁵ Mg = 10.00%

²⁶ Mg = (21.01 - 10.00)%

²⁶ Mg = 11.0%

3 0
3 years ago
You are given two fatlike solid substances and determine that sample a has a higher melting point than sample
Alchen [17]
Given that <span>sample a has a higher melting point than sample
b. Therefore, sample a is a longer chain of a </span><span>fatlike solid substance. It could also be that the bonds present in sample a is much stronger which will require more energy to break. Hope this answers the question.</span>
5 0
3 years ago
Determine the mass of CaCO3 required to produce 40.0 mL CO2 at STP. Hint use molar volume of an ideal gas (22.4 L)
cupoosta [38]

Answer:

m_{CaCO_3}=0.179gCaCO_3

Explanation:

Hello,

In this case, since the undergoing chemical reaction is:

CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

The corresponding moles of carbon dioxide occupying 40.0 mL (0.0400 L) are computed by using the ideal gas equation at 273.15 K and 1.00 atm (STP) as follows:

PV=nRT\\\\n=\frac{PV}{RT}=\frac{1.00 atm*0.0400L}{0.082\frac{atm*L}{mol*K}*273.15 K})=1.79x10^{-3} mol CO_2

Then, since the mole ratio between carbon dioxide and calcium carbonate is 1:1 and the molar mass of the reactant is 100 g/mol, the mass that yields such volume turns out:

m_{CaCO_3}=1.79x10^{-3}molCO_2*\frac{1molCaCO_3}{1molCO_2} *\frac{100g CaCO_3}{1molCaCO_3}\\ \\m_{CaCO_3}=0.179gCaCO_3

Regards.

3 0
4 years ago
Cuales son todas las propiedades periodicas
Naily [24]

Answer: chicken nugget

Explanation:

3 0
3 years ago
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