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kaheart [24]
3 years ago
14

The mid-atlantic ridge crosses through iceland. physical features such as tensional fractures and cinder cone volcanoes are all

aligned ne-sw. what does this indicate about the directions the tectonic plates are moving?
Physics
1 answer:
nlexa [21]3 years ago
8 0
This indicates that they are moving away from each other, meaning that they form a divergent plate boundary, between the two continental plates, the Eurasian Plate moving eastward, and the North American Plate moving west, this forms the Mid Atlantic Ridge.<span>
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Hiw many times lager then a centimeter is a dekagram​
Digiron [165]

Answer: 1 000 times

Explanation: 1 000 centimetre is equal to 1 dekacemetre.

Using conversion will apply in converting every number.

6 0
3 years ago
*Urgent* I WILL GIVE BRAINLIEST
Butoxors [25]

Answer:

walking to school

Explanation:

Driving a car to school

, and taking the bus to school​ both take up energy, unlike walking to school.

unless ur talking about energy, counting energy you produce and use to complete things, then it would be the 3rd one, taking the bus to school.

4 0
3 years ago
What are 5 examples of pseudoscience that can be found on the Internet?
mel-nik [20]

-- flat Earth
-- no moon landings
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7 0
3 years ago
A high school physics instructor catches one of his students chewing gum in class. He decides to discipline the student by askin
kap26 [50]

Answer:

a) \omega \approx 219.911\,\frac{rad}{s}, b) \alpha = 16.916\,\frac{rad}{s^{2}}, c) a_{t} = 1.776\,\frac{m}{s^{2}}, d) a_{n} = 5077.889\,\frac{m}{s^{2}}, e) The direction of the centripetal acceleration experimented by the gum goes to the center of rotation, f) Zero, g) v = 23.091\,\frac{m}{s}.

Explanation:

a) The maximum angular velocity of the fan is:

\omega = (35\,\frac{rev}{s} )\cdot (\frac{2\pi\,rad}{1\,rev} )

\omega \approx 219.911\,\frac{rad}{s}

b) The angular acceleration of the fan is:

\alpha = \frac{\omega-\omega_{o}}{t}

\alpha = \frac{219.911\,\frac{rad}{s}-0\,\frac{rad}{s}}{13\,s}

\alpha = 16.916\,\frac{rad}{s^{2}}

c) The magnitude of the tangential aceleration is:

a_{t} = (16.916\,\frac{rad}{s^{2}} )\cdot (0.105\,m)

a_{t} = 1.776\,\frac{m}{s^{2}}

d) The magnitude of the centripetal acceleration is:

a_{n} = (219.911\,\frac{rad}{s} )^{2}\cdot (0.105\,m)

a_{n} = 5077.889\,\frac{m}{s^{2}}

e) The direction of the centripetal acceleration experimented by the gum goes to the center of rotation.

f) When fan is at full speed, it rotates at constant rate and, hence, there is no angular acceleration. Besides, the tangential acceleration experimented by the gum is zero.

g) The linear speed of the gum is:

v = (219.911\,\frac{rad}{s} )\cdot (0.105\,m)

v = 23.091\,\frac{m}{s}

5 0
3 years ago
Calculate the upthrust aciting on a body if its
Zepler [3.9K]

Answer:

As a body moving upward

T=real weight + apparent weight

T=550+490

T=1040

hope u will get the answer:)

Explanation:

7 0
3 years ago
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