1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alexandra [31]
3 years ago
14

Where do you see triangulation used on this structure? Explain how triangulation​

Physics
1 answer:
Olegator [25]3 years ago
3 0
I like your profile picture:)
You might be interested in
What changes occurred when Zoroastrianism became a state religion during the Sasanian Empire?
statuscvo [17]
Zoroastrianism affected the way the Persians governed their subjects by allowing the territories under their rule to worship their own religion.
8 0
3 years ago
Energy is the capacity to do what ? motion or work
Ber [7]

Answer:

energy is the capacity to do work

8 0
3 years ago
A monochromatic light passes through a narrow slit and forms a diffraction pattern on a screen behind the slit. As the slit widt
maw [93]

Answer:

shrinks with all the fringes getting narrower

Explanation:

As the light passes through the slit, the diffraction pattern shrinks, as the waves have more opening to penetrate, and the fringes becomes more narrow as a result of that, The opposite happens as the conditions are reversed.

8 0
3 years ago
A charge of 7.2 × 10-5 C is placed in an electric field with a strength of 4.8 × 105 StartFraction N over C EndFraction. If the
barxatty [35]

Answer:

2.2 meters

Explanation:

Potential energy, PE created by a charge, q at a radius r from the charge source, Q,  is expressed as:

KE=\frac{kQq}{r}\     \ \ \ \ \ \ ...i

k is Coulomb's constant.

#The electric field,E at radius r is expressed as:

E=\frac{kQ}{r^2}\ \ \ \ \ \ \ \ \ \ ...ii

From i and ii, we have:

KE=Eqr

r=(KE)/Eq

#Substitute actual values in our equation:

r=\frac{75J}{(7.2\times 10^{-5}C)(4.8\times 10^5 V/m)}\\\\=2.1701\approx2.2\ m

Hence, the distance between the charge and the source of the electric field is 2.2 meters

7 0
3 years ago
Read 2 more answers
A block is resting on a platform that is rotating at an angular speed of 2.4 rad/s. The coefficient of static friction between t
Sloan [31]

Answer:

r = 0m is the Minimum distance from the axis at which the block can remain in place wothout skidding.

Explanation:

From a sum of forces:

Ff = m*a   where Ff = μ * N    and a = \frac{V^2}{r}=\omega^2*r

N - m*g = 0   So, N = m*g.   Replacing everything on the original equation:

\mu*m*g = m*\omega^2*r   (eq2)

Solving for r:

r = \frac{\mu*g}{\omega^2}=1.41m

If we analyze eq2 you can conclude that as r grows, the friction has to grow (assuming that ω is constant), so the smallest distance would be 0 and the greatest 1.41m. Beyond that distance, μ has to be greater than 0.83.

4 0
3 years ago
Other questions:
  • John is running down the street and hears dogs barking in the distance. How do the sound waves change as John approaches the bar
    12·1 answer
  • The base si unit for electric is the
    11·1 answer
  • There are 3.78 liters in one gallon, therefore 3.78L = 1 Gallon. If I need 58 half-gallon containers for my boat, determine the
    5·1 answer
  • Explain how these convection currents cause the crust of the Earth to <br> move
    8·1 answer
  • This type of stretch keeps your heart rate elevated and muscles warm.
    7·2 answers
  • A football is thrown horizontally with an initial velocity of (16.6 m/s)x^. ignoring air resistance, the average acceleration of
    12·2 answers
  • Suggest why natural gas from different countries has a different percentage to hydrocarbons
    14·1 answer
  • 1 Write 7 next to the statements that are true.
    5·1 answer
  • How much force is needed to lift a 25 kg mass at a constant velocity?
    7·1 answer
  • you throw a ball toward a wall at a speed 25.0 m/s and at an angle 40° above the horizontal. the wall is distance d = 22.0 m fro
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!