Where do you see triangulation used on this structure? Explain how triangulation

When light waves travel, they _____.

Sedbober [7]

I think the answer is d!

8 0

4 years ago

Read 2 more answers

A thunderclap sends a sound wave through the air and the ocean below. The

marysya [2.9K]

Answer:

C. 14.93 m

Explanation:

The given frequency of the wave, f = 100 Hz

The given equation for the wave speed, <em>v</em>, is presented as follows;

v = f × λ

The speed of sound in water, v = 1,493 m/s

Therefore, we get;

The wavelength, λ = v/f

∴ λ = 1,493 m/s/(100 Hz) = 14.93 m

The wavelength, λ = 14.93 m.

8 0

3 years ago

for a moving object distance covered by it is always greater than or equal to the displacement of the object in a given time. ex

AleksandrR [38]

<h3><u>Answer</u></h3>

Distance is equal to the Total Distance covered by a body, from the initial till the final point $.$

Displacement is equal to the shortest distance between two points.

So we known that Distance can only be equal to or greater than the displacement and can never be shorter than the displacement.

This is just common sense how can anything be shorter than the shortest path itself. But it can be equal to the shortest path

☯ Distance is a scalar quantity and has only magnitude but no direction.

☯ Displacement is a vector quantity and has both magnitude and direction.

☯ Distance can only have +ve values whereas displacement can be +ve, -ve or even be zero.

6 0

3 years ago

The driver of a pickup truck accelerates from rest to a speed of 37 mi/hr over a horizontal distance of 215 ft with constant acc

ZanzabumX [31]

Answer:

Maximum shearing force developed in each of the two pegs during acceleration is 1830 lbf

Explanation:

First we will find the acceleration of pickup truck.

As, the acceleration is uniform, therefore we can use Newton's third equation of motion:

2as = $V_{f}^{2}-V_{i}^{2}$

First convert speed into ft/sec

1 mile/hr = 1.47 ft/sec

therefore,

37 mile/hr = 37 x 1.47 ft/sec

37 mile/hr = 54.39 ft/sec

with initial speed 0 ft/sec (starting from rest), using in equation of motion:

a = [(54.39 ft/sec)² - (0 ft/sec)²]/2(215 ft)

a = 6.88 ft/sec²

Now, the total shear force will be given by Newton's second law of motion:

F = ma

F = (460 lbm +72 lbm)(6.88 ft/sec²)

F = 3660 lbf

Now for the max shear force in each of the two pegs we divide total fore by 2:

Force in each peg = F/2 = (3660 lbf)/2

<u>Force in each peg = 1830 lbf</u>

6 0

3 years ago

A circle has a radius of 10 inches. Find the approximate length of the arc intersected by a central angle of mc001-1. Jpg 6. 67

Andrei [34K]

The approximate length of the arc intersected by the central angle is 20.94 inches.

The given parameters:

<em>Radius of the circle, r = 10 inches</em>
<em>Central angle, </em> $\theta = \frac{2\pi }{3} \ rad$ <em />

<em />

The approximate length of the arc intersected by the central angle is calculated as follows;

S = rθ

where;

<em>S is the length of the arc</em>

Substitute the given parameters and solve for the length of the arc

$S = 10 \ in \times \frac{2\pi }{3} \\\\S = 20.94 \ inches$

Thus, the approximate length of the arc intersected by the central angle is 20.94 inches.

<em>Your question is not complete, find the complete question below:</em>

A circle has a radius of 10 inches. Find the approximate length of the arc intersected by a central angle of $\frac{2\pi}{3}$ .

Learn more about length of arc here: brainly.com/question/2005046

5 0

3 years ago

Where do you see triangulation used on this structure? Explain how triangulation​

Where do you see triangulation used on this structure? Explain how triangulation