Inertia and force
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Answer:
7.5 km/hr
Explanation:
All you have to do is divide 15 km by 2 hours and you get 7.5 km/hr.
Answer:
C.
The particles in longitudinal waves travel parallel to the direction of the wave, whereas the particles in transverse waves travel perpendicular to the direction of the wave.
Explanation:
Longitudinal waves are waves that propagates energy from their source by movement of particles in a direction parallel to the wave motion.
Transverse waves produce oscillations that are perpendicular to the direction of propagation.
- Examples of longitudinal waves are sound waves, seismic p-waves
- Examples of transverse waves are electromagnetic waves
A wave is a disturbance that transmits energy from one point to another.
Answer:
Inductance, L = 0.0215 Henry
Explanation:
Given that,
Capacitance of the capacitor, ![C=7.7\ nF=7.7\times 10^{-9}\ F](https://tex.z-dn.net/?f=C%3D7.7%5C%20nF%3D7.7%5Ctimes%2010%5E%7B-9%7D%5C%20F)
Potential difference, V = 12 V
The period of oscillation, ![t=8.1\times 10^{-5}\ s](https://tex.z-dn.net/?f=t%3D8.1%5Ctimes%2010%5E%7B-5%7D%5C%20s)
At resonance, the angular velocity is given by :
![\omega=\dfrac{1}{\sqrt{LC} }](https://tex.z-dn.net/?f=%5Comega%3D%5Cdfrac%7B1%7D%7B%5Csqrt%7BLC%7D%20%7D)
![\dfrac{2\pi}{t}=\dfrac{1}{\sqrt{LC} }](https://tex.z-dn.net/?f=%5Cdfrac%7B2%5Cpi%7D%7Bt%7D%3D%5Cdfrac%7B1%7D%7B%5Csqrt%7BLC%7D%20%7D)
![L=\dfrac{t^2}{4\pi^2C}](https://tex.z-dn.net/?f=L%3D%5Cdfrac%7Bt%5E2%7D%7B4%5Cpi%5E2C%7D)
![L=\dfrac{(8.1\times 10^{-5})^2}{4\pi^2\times 7.7\times 10^{-9}}](https://tex.z-dn.net/?f=L%3D%5Cdfrac%7B%288.1%5Ctimes%2010%5E%7B-5%7D%29%5E2%7D%7B4%5Cpi%5E2%5Ctimes%207.7%5Ctimes%2010%5E%7B-9%7D%7D)
L = 0.0215 Henry
So, the inductance of the coil is 0.0215 Henry. Hence, this is the required solution.
Answer:
![P=1139.16384mmHg](https://tex.z-dn.net/?f=P%3D1139.16384mmHg)
Explanation:
Given data
![R=0.08206(\frac{L.Atm}{mol.K} )\\Density=2.697g/L\\Temperature=298K\\f.wt=44(g/mol)\\](https://tex.z-dn.net/?f=R%3D0.08206%28%5Cfrac%7BL.Atm%7D%7Bmol.K%7D%20%29%5C%5CDensity%3D2.697g%2FL%5C%5CTemperature%3D298K%5C%5Cf.wt%3D44%28g%2Fmol%29%5C%5C)
To find
Pressure
Solution
From Ideal gas law we know that
![PV=nRT\\P=(nR\frac{T}{V} )=(R(\frac{mass}{f.wt} )(\frac{T}{V} ))\\P=R(\frac{mass}{volume}) (\frac{T}{f.wt} )=R(Density)(\frac{T}{f.wt} )](https://tex.z-dn.net/?f=PV%3DnRT%5C%5CP%3D%28nR%5Cfrac%7BT%7D%7BV%7D%20%29%3D%28R%28%5Cfrac%7Bmass%7D%7Bf.wt%7D%20%29%28%5Cfrac%7BT%7D%7BV%7D%20%29%29%5C%5CP%3DR%28%5Cfrac%7Bmass%7D%7Bvolume%7D%29%20%28%5Cfrac%7BT%7D%7Bf.wt%7D%20%29%3DR%28Density%29%28%5Cfrac%7BT%7D%7Bf.wt%7D%20%29)
Substitute the given values to find pressure
So
![P=(0.08206\frac{L.Atm}{mol.K} )(2.697g/L)(298K)(44g/mol)^{-1}\\ P=1.4989Atm\\](https://tex.z-dn.net/?f=P%3D%280.08206%5Cfrac%7BL.Atm%7D%7Bmol.K%7D%20%29%282.697g%2FL%29%28298K%29%2844g%2Fmol%29%5E%7B-1%7D%5C%5C%20P%3D1.4989Atm%5C%5C)
Convert Atm to mmHg
Multiply the pressure values by 760
So
![P=1139.16384mmHg](https://tex.z-dn.net/?f=P%3D1139.16384mmHg)