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Anna11 [10]
3 years ago
13

A roller coaster car is loaded with passengers and has a mass of 500 kg along with a speed of 18 meters/second at the dip. The r

adius of curvature of the track at the bottom point of the dip is 12 meters (gravity = 9.8 meters/second2). What force is exerted on the roller coaster car by the track at the bottom of the dip?
Physics
2 answers:
GenaCL600 [577]3 years ago
7 0
The roller coaster is moving in a circular path, so the force that must be computed is the centripetal force. The centripetal force is the force acting on an object undergoing circular motion and is directed towards the center of the circular path. This is computed using:
F = mv²/r
F = (500 * 18²) / 12
F = 13,500 N

Now, at the bottom of the track, the track is also supporting the weight of the car and its passengers, which is:
W = mg
W = 500 * 9.81
W = 4,905 N

The total reactive force exerted by the track to counter the centripetal force and the weight of the car is:
F = 13,500 + 4,905
F = 18,405 Newtons
Pachacha [2.7K]3 years ago
6 0

the answer is D on Plato.

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Answer: 0.69\°

Explanation:

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\delta=2 sin^{-1}(\frac{d}{2D})

Where:

d=16 m is the actual diameter

D=1338 m is the distance to the spherical object

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\delta=2 sin^{-1}(\frac{16 m}{2(1338 m)})

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3 0
3 years ago
A hydrogen atom has a diameter of about 10 nm. Express this diameter in meters. Express this diameter in millimeters. Express th
Fynjy0 [20]
So, the first question is: how many meters are 10 nm?

1nm =<span>0.000000001 m.

So 10 nanometers are </span><span>0.00000001 m!

Now, how many milimeter are those?
let's start with meters, 1 meter are 1000 milimeters.
so </span>
0.00000001*1000=0.<span><span>00001</span> m!

now, micrometers .1 micrometer are 1000 nanometers.
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8 0
3 years ago
A 1400-kg car is traveling with a speed of 17.7 m/s. What is the magnitude of the horizontal net force that is required to bring
AleksandrR [38]

Answer:

The magnitude of the horizontal net force is 13244 N.

Explanation:

Given that,

Mass of car = 1400 kg

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Distance = 33.1 m

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Using equation of motion

v^2-u^2=2as

Where, u = initial velocity

v = final velocity

s = distance

Put the value in the equation

0-(17.7)^2=2a\times 33.1

a=\dfrac{-(17.7)^2}{33.1}

a=-9.46\ m/s^2

Negative sign shows the deceleration.

We need to calculate the net force

Using newton's formula

F = ma

F =1400\times(-9.46)

F=-13244\ N

Negative sign shows the force is opposite the direction of the motion.

The magnitude of the force is

|F| =13244\ N

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5 0
3 years ago
A ball is dropped from some height. It bounces off the floor and rebounds with a speed that is one-half the speed it had just be
Arada [10]

Answer:

The correct option is C

Explanation:

According to third equation of motion, v

2

=u

2

+2ax

Here, u=0 m/s

a=−g and x=−h

Negative sign indicates downward direction. Displacement and acceleration both are downwards.

So,v=±

2(−g)(−h)

​

We take minus sign because it is downwards.

v=−

2gh

​

After bouncing. velocity becomes 80% of v, i.e.,

v

′

=+0.8

2gh

​

 

(positive sign because the direction of ball has reversed after bouncing and is upwards.

Applying third equation of motion again, for u=v

′

, v=0 and a=−g

v

2

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Thus,

0=0.64(2gh)+2(−g)x

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3 0
2 years ago
If you operate a 2.0 kilowatt for 2 hours how much energy do you use
kap26 [50]

Answer:

4 kWh/day

Explanation:

hope this helps!

~mina-san

3 0
3 years ago
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