Answer:
E=
Explanation:
We are given that
Charge on ring= Q
Radius of ring=a
We have to find the magnitude of electric filed on the axis at distance a from the ring's center.
We know that the electric field at distance x from the center of ring of radius R is given by

Substitute x=a and R=a
Then, we get




Where K=
Hence, the magnitude of the electric filed due to charged ring on the axis of ring at distance a from the ring's center=
The pressure drop in pascal is 3.824*10^4 Pascals.
To find the answer, we need to know about the Poiseuille's formula.
<h3>How to find the pressure drop in pascal?</h3>
- We have the Poiseuille's formula,

- where, Q is the rate of flow, P is the pressure drop, r is the radius of the pipe, is the coefficient of viscosity (0.95Pas-s for Glycerin) and l being the length of the tube.
- By substituting values and rearranging we will get the pressure drop as,

Thus, we can conclude that, the pressure drop in pascal is 3.824*10^4.
Learn more about the Poiseuille's formula here:
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A-11 polar easterlies
b-8 winds blowing between the equator and 30° N and south
c-10
d-9
Answer:
993.52 Hz
Explanation:
The frequency of sound emitted by the stationery train is 1057 Hz.
The car travels away from the train at 20.6 m/s.
The frequency the observer hears is given by the formula:

where v = velocity of sound = 343 m/s
vo = velocity of observer
f = frequency from source
This phenomenon is known as Doppler's effect.
Therefore:

The frequency heard by the observer is 993.52 Hz.
Answer:
An interaction of one object with another object results in a force between the two objects. Thus, at-least two objects must interact for a force to come into play.