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3 years ago

Which of Newton’s laws did Nikolas use to have to calculate this force

Physics

1 answer:

devlian [24]3 years ago

6 0

Answer:

the second force

Explanation:

this is the answer i hade for mine

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A 110-g bullet is fired from a rifle having a barrel 0.636 m long. Choose the origin to be at the location where the bullet begi

astraxan [27]

Data:
mass = 110-g bullet
d = 0.636 m
Force = 13500 + 11000x - 25750x^2, newtons.

a) Work, W

W = ∫( F* )(dx) =∫[13500+ 11000x - 25750x^2] (dx) =

W = 13500x + 5500x^2 - 8583.33 x^3 ] from 0 to 0.636 =

W = 8602.6 joule

b) x= 1.02 m

W = 13500x + 5500x^2 - 8583.33 x^3 ] from 0 to 1.02

W = 10383.5

c) %

[W in b / W in a] = 10383.5 / 8602.6 = 1.21 => W in b is 21% more than work in a.

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3 years ago

Mendel wanted to find out if the pattern of inheritance for one trait affected the pattern of inheritance for anther. What exper

Inga [223]

Answer is given below :

Explanation:

He tested the seed color and shape. At the same time Gregor Mendel focused his search on seed size, flower color, seed coat color, pod size, immature pod color, flower position and pea plant height.
To describe the results he drew, he coined the terms 'recessive' and 'dominant'.

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Acceleration is maximum. Velocity is decreasing. Acceleration is increasing

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A wedge shaped air film is made between two sheets of glass using a spacer at one end of the glass sheets. If light of wavelengt

pychu [463]

Answer:

1178 nm

Explanation:

We are given that

Wavelength of light= $\lambda=589nm=589\times 10^{-9} m$

$1nm=10^{-9} m$

We have to find the thickness of spacer if five dark fringes are observed between the edges of the glass.

Suppose that first dark fringe and fifth dark fringe near spacer, then the path length of light is 4 times the wavelength of light.

The light passes through air film is two times then the change in air film thickness from one edge to other is two times the wavelength of light.

Change in air film thickness from one edge to other edge is same as the thickness of spacer.

Therefore, thickness of spacer= $2\lambda$

Thickness of spacer= $2\times 589\times 10^{-9}$ m

Thickness of spacer=1178 nm

Hence, the thickness of spacer=1178 nm

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3 years ago

Subduction zones form when an oceanic plate collides with another oceanic plate or continental plate. The continental crust is l

Fed [463]

The answer is; metamorphic

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