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3 years ago

Why must you compress the air-fuel mixture inside the combustion chamber?

Engineering

2 answers:

quester [9]3 years ago

8 0

Answer:

• To heat the mixture.

Explanation:

This is because when compression occurs, the pressure under combustion chamber increases and this increases the velocity of air molecules.

As a result, average kinetic energy of the molecules increases hence heat energy increases proportionally

$.$

8090 [49]3 years ago

3 0

Answer:

all above bc heat is heat fuel is fuel

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The coefficient of performance of a reversible refrigeration cycle is always (a) greater than, (b) less than, (c) equal to the c

bezimeni [28]

Answer:

Option B is correct

Explanation:

Let

Higher temperature = $T_H$

Lower temperature = $T_L$

We know that COP is given by

$COP = \frac{T_L}{T_H-T_L}$

We see that COP is depends only on the temperature difference & Temperature difference is maximum for the Carnot cycle.

Therefore the COP of reversible refrigeration cycle is always less then the COP of an irreversible refrigeration cycle when each operates between the same two thermal reservoirs.

Therefore option B is correct

5 0

3 years ago

2. In the above figure, what type of cylinder arrangement is shown in the figure above?

Oduvanchick [21]

Answer:

C. Horizontal

Explanation:

The type of cylinder arrangement that is shown in the figure is "Horizontal"

The arrangement is actually horizontal which is known to be horizontally opposed engine. Such engine is known as flat engine. It's a piston engine that has the cylinders located on either side of a crankshaft. It is usually located at the central crankshaft. This type of engine has performance advantage over others.

5 0

4 years ago

The in situ moisture content of a soil is 18% and the moist (total) unit weight is 105 pcf. The soil is to be excavated and tran

densk [106]

Answer: Volume= 1.16 yd³

Explanation:

We are given the in-situ moisture content= 18% and moist unit weight= 105 pcf

First we find out the dry unit weight

Dry unit weight= Moist unit weight / (1+ moisture content)

Dry unit weight= $\frac{105}{1.18}$

Dry unit weight= 88.983 pcf

Now, to find the volume ( in terms of each cubic yard i.e 1 yd³ we have

Volume = Dry unit weight compacted / Dry unit weight (in-situ) * 1 yd³

Volume= $\frac{103.5}{88.983} * 1$

Volume= 1.16 yd³

6 0

4 years ago

The flowrate through a rectangular channel is 20 cfs. The upstream width of the channel is 10 ft, and the depth of the water in

Liula [17]

To solve this problem we will use the Froude number that relates the Forces of Inertia with the Forces of Gravity. There will be jump in the downstream only if Froude Number (Fr) is greater than 1 at upstream. Our values are given as,

$Q = 20cfs\\w= 10ft\\D= 1ft$