What would be the resulting molarity of a solution made by dissolving 21.9 grams of KCl in enough water to make an 869-millilite r solution? Show all of the work needed to solve this problem.
1 answer:
Molar mass KCl = 74.55 g/mol Volume = 869 mL in liters : 869 / 1000 => 0.869 L number of moles: 21.9 / 74.55 => 0.293 moles M = n / V M = 0.293 / 0.869 M = 0.337 mol/L⁻¹ hope this helps!
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