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Zigmanuir [339]
3 years ago
10

Choose the correct statement regarding the sign conventions for lenses.

Physics
1 answer:
Savatey [412]3 years ago
3 0

Answer:

a) false

b) True

c) True

d) False

e) False

Explanation:

a) False

For a diverging lens, the focal length is negative while it is positive for a converging lens

b) True

Image distances  for virtual images are always negative and it also forms on the the same side of the lens as the object and is enlarged

c) True

d) False

For a diverging lens, the focal length is negative while it is positive for a converging lens

e) False

Image distances  for virtual images are always negative and it also forms on the the same side of the lens as the object and is enlarged

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The stones are launched from the top of a tall building. One stone is thrown in a direction 15.0 ∘ above the horizontal with a s
const2013 [10]

Answer:

Maximum horizontal distance covered by both the stones will be same because the speed at which both the stones are thrown is same.

However, stone that is thrown upward will spend more time in the air as compared to the stone that is thrown downward because of the projectile and vertical component of the velocity.

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4 years ago
What type of energy is found in fossil fuels?
vladimir1956 [14]

Answer:The energy in fossil fuels (coal, oil, gas)

Explanation:

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3 years ago
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An electric motor is used to run an elevator. The total mass of the elevator car and passenger is 1600 kg. The elevator moves up
Masja [62]

Answer:

Approximately 2.7 \times 10^{4}\; {\rm W}, assuming that g = 9.81\; {\rm m\cdot s^{-2}}

Explanation:

The weight of the elevator is:

\begin{aligned}& \text{weight} \\ =\; & m\, g \\ =\; & 1600\; {\rm kg} \times 9.81\; {\rm m \cdot s^{-2}} \\ \approx\; & 15700\; {\rm N}\end{aligned}.

Since the speed of the elevator is constant, the acceleration of this elevator would be 0.

By Newton's Second Law of Motion, the net force on the elevator (proportional to acceleration) would also be 0\!. All external forces on the elevator need to be balanced in every direction.

The only two vertical forces on the elevator are:

  • the weight of the elevator (downward gravitational pull from the earth,) and
  • the upward pull from the motor.

These two forces need to balance one another. Since the weight of the elevator is approximately 15700\; {\rm N}, the upward pull of the motor would be 15700\; {\rm N}\!. in magnitude.

The direction of this upward pull is the same as the direction of the motion of this elevator. Thus, the work that the motor did on the elevator would be positive:

\begin{aligned}& \text{work} \\ =\; & F\, s \\ \approx\; & 15700\; {\rm N} \times 15.0\; {\rm m} \\ \approx\; & 2.35 \times 10^{5}\; {\rm J}\end{aligned}.

Since the velocity of the elevator is constant, instantaneous power output of the motor would be equal to the average power of the motor:

\begin{aligned}& \text{power} \\ =\; & \frac{\text{work}}{t} \\ \approx\; & \frac{2.35 \times 10^{5}\; {\rm J}}{8.82\; {\rm s}} \\ \approx\; & 2.7 \times 10^{4}\end{aligned}.

4 0
3 years ago
The mass of a cm3(cube) stone is 180.
ss7ja [257]

 Density = (mass) / (volume), no matter how large or small the sample is.

We can't calculate the density, because you left out the number for the volume.
Also, you didn't tell us the unit for the mass of 180.

a).  If the mass is 180 grams, then the density is 

                               (180 gm) / (volume) .

b).  No matter how many pieces you crush it into, and
no matter how large or small a piece is, its density is
the same.  (I just wish we knew what the density really is.)

c).  A piece may have 80 grams of mass.  It doesn't "weigh" 80 grams.

Since the density of the whole rock is  (180 gm) / (volume),
the density of any piece of it is  (180 gm) / (volume).

Multiply each side by (volume):   (Density) x (volume) = 180 gm

Divide each side by (density):        Volume = (180 gm) / (density)

We can't calculate the volume of an 80-gm piece, because
we don't know the density.  (That's because you left the volume
out of the question.)

4 0
3 years ago
A car on the highway slows for 32.0 m/s to rest as the driver approaches a traffic jam. The car has 70.0. To stop. A.Solve for t
ratelena [41]
B is the answerrrr so put it and get a A
8 0
3 years ago
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