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Alla [95]
3 years ago
11

How is a sodium ion symbol written? Na+ So+ ООО SO- Na-

Chemistry
1 answer:
Nataliya [291]3 years ago
4 0

Answer:

Na^+

Explanation:

The symbol for sodium is Na.  The term "sodium ion" assumes that the reader knows that sodium's single 3s electron is susceptible to theft by any nearby element that has a high electron affinity.  Sodium's ionization energy is low, allowing the 3s electron to move elsewhere and leave behinf a positively charged Na^+ atom.

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polet [3.4K]

Answer:

1st one

Explanation:

5 0
3 years ago
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Erioglucine is a blue-colored dye that absorbs its complementary color, red, in aqueous solution around 645 nm. Unfortunately, t
ExtremeBDS [4]

Answer:

For the control experiment: 0.0552 M of aqueous solution of erioglaucine has absorbance of 0.035 M\\

From Lambert-Beer's law we know:

Absorbance = e\cdot c \cdot l\\

Here; e is the molar absorptivity coefficient of erioglaucine

l = length of cuvette in which the solution is taken = 1 cm

A sorbance by the erioglaucine = total absorbance - absorbance by distilled water = 0.331-0.019 = 0.312

So; by putting the values in the above equation; we get:

0.312 = 0.0552 M \cdot e\cdot~1cm\\

So; e = \frac{0.331}{0.0552} M^{-1}cm^{-1}= 5.65 M^{-1}cm^{-1}

The molar absorptivity coefficient of erioglaucine is 5.65 M^{-1}cm^{-1}\\

The absorbance of erioglaucine in distilled water (contaminated with metal ions) is: 0 .217

The absorbance of distilled water is 0.019

So; absorbance of erioglaucine itself is : 0.217-0.019 = 0.198

Again using Lambert Beer law; we get:

A= e\cdot c\cdot l

0.198 = 5.65 M^{-1}cm^{-1} \cdot  c \cdot  1 cm ( c = concentrartion)

c = 0.198/5.65 M = 0.035 M

The concentration of the erioglaucine is 0.035 M\\

Explanation:

4 0
4 years ago
30.) Use Percentages: According to the data in table above, what percentage of the energy used in the United States comes from f
STatiana [176]

Answer:

im no expert i believe 42

hope it helps

Explanation:

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3 years ago
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Find the density of an object that has a mass of 28 grams and a volume of 2 points<br> 38.6 cm^3. *
Shtirlitz [24]

Answer:

<h2>0.73 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question we have

density =  \frac{28}{38.6}  \\  =0.72538...

We have the final answer as

<h3>0.73 g/cm³</h3>

Hope this helps you

4 0
3 years ago
HELPPP!!! What is the volume of a 1.31 moles sample of gas if the pressure is 904 mmHg and the temperature is 37. degrees Celsiu
Tju [1.3M]

Answer:

27.99 dm³

Explanation:

Applying

PV = nRT................ Equation 1

Where P = Pressure, V = Volume, n = number of mole, R = molar gas constant, T = Temperature.

From the question, we were aksed to find V.

Therefore we make V the subject of the equation

V = nRT/P................ Equation 2

Given: n = 1.31 moles, T = 37°C = 310K, P = 904 mmHg = (904×0.001316) = 1.1897 atm

Constant: R = 0.082 atm.dm³/K.mol

Substitute these values into equation 2

V = (1.31×310×0.082)/(1.1897)

V = 27.99 dm³

4 0
3 years ago
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