Answer:
For the control experiment:
of aqueous solution of erioglaucine has absorbance of 
From Lambert-Beer's law we know:

Here; e is the molar absorptivity coefficient of erioglaucine
l = length of cuvette in which the solution is taken = 
A sorbance by the erioglaucine = total absorbance - absorbance by distilled 
So; by putting the values in the above equation; we get:

So; 
The molar absorptivity coefficient of erioglaucine is 
The absorbance of erioglaucine in distilled water (contaminated with metal ions) is: 
The absorbance of distilled water is 
So; absorbance of erioglaucine itself is : 
Again using Lambert Beer law; we get:


c = 0.198/5.65 M = 0.035 M
The concentration of the erioglaucine is 
Explanation:
Answer:
im no expert i believe 42
hope it helps
Explanation:
Answer:
<h2>0.73 g/cm³</h2>
Explanation:
The density of a substance can be found by using the formula

From the question we have

We have the final answer as
<h3>0.73 g/cm³</h3>
Hope this helps you
Answer:
27.99 dm³
Explanation:
Applying
PV = nRT................ Equation 1
Where P = Pressure, V = Volume, n = number of mole, R = molar gas constant, T = Temperature.
From the question, we were aksed to find V.
Therefore we make V the subject of the equation
V = nRT/P................ Equation 2
Given: n = 1.31 moles, T = 37°C = 310K, P = 904 mmHg = (904×0.001316) = 1.1897 atm
Constant: R = 0.082 atm.dm³/K.mol
Substitute these values into equation 2
V = (1.31×310×0.082)/(1.1897)
V = 27.99 dm³