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alukav5142 [94]
3 years ago
12

An implanted pacemaker supplies the heart with 72 pulses per minute, each pulse providing 6.0 V for 0.65 ms. The resistance of t

he heart muscle between the pacemaker’s electrodes is 550Ω. Find (a) the current that flows during a pulse, (b) the energy delivered in one pulse, and (c) the average power supplied by the pacemaker.
Physics
1 answer:
9966 [12]3 years ago
6 0

Answer: a) 0.11 Amp b) 0.000429 Joules c) 0.000514 watt

Explanation:

a)current

I=V/r I=6.0/550 =1.1*10^-2 A

b) energy

E= 1.1*10^-2 x (6.0) x 0.00065s(<-- remember to convert ms to seconds) = 0.000429J

C) Average power

P = (0.000429 x 72) / 60

P = 0.000514 W

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A cylindrical piece of wood of height H, radius r, and uniform density rhoc is bobbing up and down in still water with its axis
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Answer:

r\sqrt{\frac{g\pi\rho_w}{m}}

Explanation:

As the buoyant force is proportional to the length of which the wood is submerged in water, we can model the buoyant force as a spring force and the bobbing wood is a simple harmonic motion described as A cos (ωt + φ) where

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where k (N/m) is the "spring" buoyant constant and m is the mass of wood

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Since the cylindrical has a form of AL where A is the base area and L is the length submerged

F_b = AL\rho_w g = (\pi r^2\rho_w g) L

As L can be treated as the spring "stretched/compressed" length, the rest is k:

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k = (\pi r^2\rho_w g)

Therefore

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