Please don't use a car's ignition coil as an example. Let's just say it's an ordinary transformer. If you connect 1800 volts AC to one side of the transformer and you get 12 volts out of the other side, then the turns of wire are in the same ratio as the voltages ... 1800/12 = 150.
A car coil doesn't work like an ordinary transformer. In a car, you put 12-volt pulses into one side, and you get voltage out of the other side that's high enough to fire spark plugs and ignite gasoline.
So you've actually got the primary and secondary windings labeled in reverse in the question, and you're actually using it as a step-DOWN transformer.
Answer:
9.6 rad/s
Explanation:
= length of the metal rod = 50 cm = 0.50 m
= Mass of the long metal rod = 780 g = 0.780 kg
Moment of inertia of the rod about one end is given as
= force applied by the hammer blow = 1000 N
Torque produced due to the hammer blow is given as
= time of blow = 2.5 ms = 0.0025 s
= Angular velocity after the blow
Using Impulse-change in angular momentum, we have
power ratings basically just compare with how many watts are used, like a tackle in football compares to a car engine
Answer:
the inner core if I believe. I apologize if I am incorrect
Answer:1.71 m/s
Explanation:
Given
mass of Susan 
Inclination 
Tension 
coefficient of Friction 
Resolving Forces Along x axis
where 
since there is no movement in Y direction therefore
and 
Thus 
Work done by applied Force is equal to change to kinetic Energy
