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2 years ago

13

I live for love, but i cant have it

2 answers:

luda_lava [24]2 years ago

8 0

Answer:

Dont worry ,

One day you will find the love of your life

Explanation:

arsen [322]2 years ago

6 0

Just wait for that love cause soon your love you like to have is coming soon it's like Jesus,, jesus is coming soon and all people like to see him but Jesus said "I'm coming soon my children" just wait for are love life cause if you find now I think you feel hurt soon

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The universal law of gravity states that all objects attracts all other objects.

andreev551 [17]

When the object is big enough to contract itself into a ball.

4 0

3 years ago

A single conservative force Fx = (6.0x  12) N (x is in m) acts on a particle moving along the x axis. The potential energy asso

jasenka [17]

Answer:

$U(3)=-43J$

Explanation:

Potential energy is minus the integral of Fdx. Doing the integration yields:

$U=\int\limits {6.0x+12}\, dx$

$U=-3x^2-12x+C$

$U(0)=20J$

so

$U(0)=-3(0)^2+12(0)+C=20$

$C=20$

Now for x=3.0m

$U(3)=-3*(3)^2-12(3)+20$

$U(3)=-43J$

6 0

3 years ago

Which of the statements given below is correct? 1. In winter, the wind blows from land to oceans. 2. In summer , the winds blow

densk [106]

Answer:

The second one should be correct

3 0

3 years ago

When an excited electron falls from n = 3 to n = 2, a red radiation in the Balmer series emitted. What is the frequency of this

vichka [17]

Answer:

The frequency of this photon is $4.57\times10^{14}\ Hz$

(D) is correct option.

Explanation:

Given that,

Excited states,

$n=3$

$n=2$

We need to calculate the wavelength

Using formula for energy

$E=13.6(\dfrac{1}{n^2}-\dfrac{1}{m^2})$

$E=13.6(\dfrac{1}{4}-\dfrac{1}{9})$

$E=1.888\ eV$

$E=1.888\times1.6\times10^{-19}\ J$

$E=3.0208\times10^{-19}\ J$

We need to calculate the frequency

Using formula of frequency

$E=hf$

$f=\dfrac{E}{h}$

Where, E =energy

$f=\dfrac{3.0208\times10^{-19}}{6.63\times10^{-34}}$

$f=4.57\times10^{14}\ Hz$

Hence, The frequency of this photon is $4.57\times10^{14}\ Hz$

4 0

3 years ago

Using a coil made of 219 turns of single‑strand copper wire, you use a motor to rotate the coil at a constant angular speed of 9

mylen [45]

Answer:

0.0222T

Explanation:

Frequency (f) =90 rev/s

Voltage = 1.15 v

Radius of coil = 1.00cm

= 0.01m

No of turns of wire (N) = 291

ω = 2πf

ω = 2π(90)

ω = 180π

A(t)= πr².sin ωt

= π(0.01)². Sin180πt

= 0.0001π.sin180πt

Differentiate A(t) with respect to t

dA/dt = 0.0001π . 180π . cos 180πt

EMF = - NB(dA/dt)

B = EMF/N(dA/dt)

B = 1.15/ -291(0.0001π . 180π . cos 180πt)

At the moment of induced voltage, cos180π = 1

B = 1.15/ -291(0.0001π . 180π . 1)

B = 1.15/ -51.7

B = 0.0222 T

The strength of the magnetic field = 0.0222T

6 0

4 years ago