<em>Energy</em><em> </em><em>can</em><em> </em><em>neither </em><em>be</em><em> </em><em>created </em><em>nor</em><em> </em><em>be</em><em> </em><em>destroyed</em><em> </em><em>but</em><em> </em><em>can</em><em> </em><em>be</em><em> </em><em>converted</em><em> </em><em>from</em><em> </em><em>one</em><em> </em><em>form</em><em> </em><em>to</em><em> </em><em>another </em><em>.</em>
It causes the global pattern of wind and precipitation (such as rain, snow, or hail).
I believe the answer is free electrons
To solve this problem we will apply the concepts related to the double slit-experiment. Under this concept we understand the relationship between the minimum angle, depending on the order of the fringes, the wavelength and the distance between slits. Therefore we have the following relation,
Here,
m = Order of the fringes
D = Distance between slits
= Wavelength
Replacing with our values we have,
Through the relationship between distances then we have that the basic amplification distance is given by the relationship between the distance of the slit L and the angle, then
Thus the width of the central maximum is
Therefore the widht is 0.466m
Answer:
Charge on Moon and Earth is 5.43x10¹³ C .
Explanation:
Gravitational force is the force of attraction between any two bodies having mass while Electrostatic force is the force experienced by two charge bodies. Electrostatic force can be attractive or repulsive.
Let M and m be the mass of Earth and Moon respectively, d is the distance between Earth and Moon and q be the charge on Earth and -q be on the Moon.
Gravitational force, F₁ =
Here G is gravitational constant.
Electrostatic force, F₂ =
Here k is Coulomb constant.
According to the problem, the gravitational force between Earth and Moon is equal to the electrostatic force between them.
F₁ = F₂
=
=
Put 6.07x10⁻¹¹ N m²/kg² for G, 5.97x10²⁴ kg for M, 7.34x10²² kg for m and 9x10⁹ N m²/C² in the above equation.
= q²
q =
q = 5.43x10¹³ C