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bogdanovich [222]
3 years ago
13

A 200 W vacuum cleaner is powered by an electric motor whose efficiency is 70%. (Note that the electric motor delivers 200 W of

net mechanical power to the fan of the cleaner). Calculate the rate at which this vacuum cleaner supply energy to the room when running. ?
Engineering
1 answer:
Goshia [24]3 years ago
5 0

Answer:

The rate at which this vacuum cleaner supply energy to the room when running is 285.71 Watts.

Explanation:

power efficiency of electric motor = 70% = 0.70

The power output of the vacuum cleaner =P_o= 200 W

The power output of the vacuum cleaner = P_i

Efficiency=\frac{P_o}{P_i}

0.70=\frac{200 W}{P_i}

P_i=\frac{200 W}{0.70}=285.71 W

The rate at which this vacuum cleaner supply energy to the room when running is 285.71 Watts.

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