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Paul [167]
2 years ago
10

So I kicked my leg in the air trying to do something but I slipped cause I had socks on. I hit the ground hard with my left hand

. It bent back pretty far. It hurts to move. But like I said it isn't swollen. Is it broken?
1. Hurts to move
2. Not swollen
3. Hurts in general
4. Can't put any weight on it or my wrist feels like exploding
5. Can't pick up my water bottle which is pretty light
6. Hurts sort of when I move my fingers
7. Feels weird when I move it and after I move it my wrist is pounding with pain
Is it broken? Should I convince my mom to take me to get an x-ray? Should I get an x-ray? Please let me know!
Physics
1 answer:
evablogger [386]2 years ago
4 0

Answer:

You probably just sprained it, but if it starts swelling and you can't move it at all.. I think you should get an x-ray

But for now, grab a cold compress and place it where it hurts

Explanation:

Stay safe and feel better, my friendd!

Have a wonderful day:)

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Answer:

Wheel A.

Explanation:

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Wheel A

I_{A} = M\cdot R^{2}

Wheel B

I_{B} = \frac{1}{2}\cdot M \cdot (2\cdot R)^{2}

I_{B} = 2\cdot M\cdot R^{2}

The wheel A accelerates faster in response to the torque.

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3 years ago
A horizontal spring with spring constant 130 N/m is compressed 17 cm and used to launch a 2.8 kg box across a frictionless, hori
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Explanation:

The given data is as follows.

        k = 130 N/m,       \Delta x = 17 cm = 0.17 m   (as 1 m = 100 cm)

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When the spring is compressed then energy stored in it is as follows.

             Energy = \frac{1}{2}kx^{2}

Now, spring energy gets converted into kinetic energy when the box is launched.

So,    \frac{1}{2}kx^{2} = \frac{1}{2}mv^{2}

   \frac{1}{2} \times 130 \times (0.17)^{2} = \frac{1}{2} \times 2.8 \times v^{2}

          v^{2} = \frac{3.757}{2.8}

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Now,

           Frictional force = \mu \times mg

                                    = 0.15 \times 2.8 \times 9.8

                                    = 4.116 N

Also,  Kinetic energy = work done by friction

           \frac{1}{2}mv^{2} = F_{f} \times d

           \frac{1}{2} \times 2.8 \times (1.15)^{2} = 4.116 \times d

             1.8515 = 4.116 \times d

                 d = 0.449 m

Thus, we can conclude that the box slides 0.449 m across the rough surface before stopping.

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Answer:

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i believe this is the correct answer

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