Answer:
1.38x10⁻⁴ M
Explanation:
First, we <u>calculate the pOH of the solution</u>, using the <em>given pH</em>:
- pOH = 14 - pH
- pOH = 14 - 10.44
- pOH = 3.56
Now we <u>calculate the concentration of OH⁻</u>, using<em> the pOH</em>:
- pOH = -log[OH⁻]
- [OH⁻] =
= 2.75x10⁻⁴ M
Following the reaction Ca(OH)₂ → Ca⁺² + 2OH⁻, we divide [OH⁻] by 2 to calculate [Ca(OH)₂]:
- [Ca(OH)₂] = 2.75x10⁻⁴ M / 2
- [Ca(OH)₂] = 1.38x10⁻⁴ M