Answer:
It should be A. I've never heard of freezing of sediments
Answer: The correct answer is option B.
Explanation:
- Ionic bond is formed when there is complete transfer of electrons from one element to another.
- Covalent bond is formed by the sharing of electrons between two elements.
- Metallic bond is formed when two metals combine together.
Electronic Configuration of Group VII-A :
This group require 1 electron to attain stable electronic configuration.
Electronic configuration of Group I-A :
This group will loose 1 electron to attain stable electronic configuration.
So, there will be complete transfer of electron from Group VII-A to Group I-A and hence, will form ionic bond between them.
Hence, the correct option is B.
Answer:
Independent Variable: The thing in an experiment which is changed.
Dependent Variable: The thing in an experiment which is affected by the change. (In other words, it's affected by the independent variable.)
Control Variable: The other factors of the experiment that remain unchanged.
For example, say you want to do an experiment about the effects of water on plant height. So, the independent variable, or the thing that is changed would be the amount of water, and the dependent variable would be the plant height, as the plant height is directly affected by the independent variable. Lastly, for this to be a fair experiment, there must be control variables. For example, all of the plants should be put in a room with equal temperature, they should get the same amount of sunlight, etc.
I hope this answers your question- feel free to ask me if you need any more help.
Answer:
The most important thing to know is that an α-particle (alpha particle) is a helium nucleus.
Explanation:
It contains 2 protons and 2 neutrons, for a mass number of 4.
During α-decay, an atomic nucleus emits an alpha particle. It transforms (or decays) into an atom with an atomic number 2 less and a mass number 4 less.
Thus, radium-226 decays through α-particle emission to form radon-222 according to the equation:
226
88
Ra
→
222
86
Rn
+
4
2
He
Note that the sum of the subscripts (atomic numbers or charges) is the same on each side of the equation. Also, the sum of the superscripts (masses) is the same on each side of the equation.
EXAMPLE
Write a balanced nuclear equation for the α decay of polonium-208.
Solution
The unbalanced equation is
208
84
Po
→
4
2
He
+
X
The superscript of
X
must be 208 – 4 = 204.
The subscript of
X
must be 84 – 2 = 82.
Element 82 is Pb. So the equation is
208
84
Po
→
4
2
He
+
204
82
Pb
Explanation:hope this is right and helps