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Jobisdone [24]
3 years ago
13

In 100 grams of sweet peas there are 14.5 carbohydrates,5.7 grams of sugars,5.1 grams of dietary fiber, 5.4 grams of protein and

0.4 grams of fat what is the percent composition of each?
Chemistry
1 answer:
Serjik [45]3 years ago
6 0
Percent composition is the quantity or number of parts of a component contained in 100 parts of the total.

Given the the total is 100 g, the reported quantities for each component are the same percent.

Then, the percent composition of each as part of the entire sweet peas is:

Carb: 14.5%
Sugar: 5.7%
Diet. fiber: 5.1%
Prot: 5.4%
Fat: 0.4%

The rest to make the 100% is supposed to be water.

You could also find the percent composition in dry basis, which is done in this way (this is not what the question asks but it is good to know it).

Total components without water: 14.5 + 5.7 + 5.1 + 5.4 + 0.4 = 31.1 grams

Now divide each content by the total (31.1) and multiply by 100.

I will do one example:

Carbs: [14.5 / 31.1 ] * 100 = 46.6%

 

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3 years ago
A 0.75M solution of CH3OH is prepared in 0.500 kg of water. How many moles of CH3OH are needed?
4vir4ik [10]

Answer:

We need 0.375 mol of CH3OH to prepare the solution

Explanation:

For the problem they give us the following data:

Solution concentration 0,75 M

Mass of Solvent is 0,5Kg

knowing that the density of water is 1g / mL,  we find the volume of water:

                           d = \frac{g}{mL} \\\\ V= \frac{g}{d}  = \frac{500g}{1 \frac{g}{mL} } = 500mL = 0,5 L

Now, find moles of CH_{3} OH are needed using the molarity equation:

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therefore the solution is prepared using 0.5 L of H2O and 0.375 moles of CH3OH,  resulting in a concentration of 0,75M

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3 years ago
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