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Jobisdone [24]
3 years ago
13

In 100 grams of sweet peas there are 14.5 carbohydrates,5.7 grams of sugars,5.1 grams of dietary fiber, 5.4 grams of protein and

0.4 grams of fat what is the percent composition of each?
Chemistry
1 answer:
Serjik [45]3 years ago
6 0
Percent composition is the quantity or number of parts of a component contained in 100 parts of the total.

Given the the total is 100 g, the reported quantities for each component are the same percent.

Then, the percent composition of each as part of the entire sweet peas is:

Carb: 14.5%
Sugar: 5.7%
Diet. fiber: 5.1%
Prot: 5.4%
Fat: 0.4%

The rest to make the 100% is supposed to be water.

You could also find the percent composition in dry basis, which is done in this way (this is not what the question asks but it is good to know it).

Total components without water: 14.5 + 5.7 + 5.1 + 5.4 + 0.4 = 31.1 grams

Now divide each content by the total (31.1) and multiply by 100.

I will do one example:

Carbs: [14.5 / 31.1 ] * 100 = 46.6%

 

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mario62 [17]

<u>Answer:</u> The freezing point of solution is 2.6°C

<u>Explanation:</u>

To calculate the depression in freezing point, we use the equation:

\Delta T_f=iK_fm

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Putting values in above equation, we get:

5.5-\text{Freezing point of solution}=1\times 5.12^oC/m\times \frac{7.99\times 1000}{178.23g/mol\times 79}\\\\\text{Freezing point of solution}=2.6^oC

Hence, the freezing point of solution is 2.6°C

8 0
3 years ago
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Answer is: 28 kJ.
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Ea(reverse) = 77 kJ/mol.
ΔH(reaction) = ?
<span>The enthalpy change of reaction is the change in the energy of the reactants to the products.
</span>ΔH(reaction) = Ea(forward) - Ea(reverse).
ΔH(reaction) = 105 kJ/mol - 77 kJ/mol.
ΔH(reaction) = 28 kJ/mol; this is endothermic reaction (ΔH <span>> 0).</span>

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