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olya-2409 [2.1K]
2 years ago
11

PLS HELP ME ASAPPPP. 50 POINTSSS

Physics
1 answer:
dybincka [34]2 years ago
4 0

Answer:

1.8 kj

Explanation:

Explanation:

A substance's specific heat tells you how much heat is required to increase the mass of

1 g

of that substance by

1

∘

C

.

The equation that establishes a rel;ationship between heat absorbed and change in temperature looks like this

q

=

m

⋅

c

⋅

Δ

T

, where

q

- heat absorbed

m

- the mass of the sample

c

- the specific heat of the substance

Δ

T

- the change in temperature, defined as the difference between the final temperature and the initial temperature of the sample

You have all the information needed to find the amount of heat required to increase the temperature of your sample of mercury by that many degrees Celsius, so just rearange the above equation and solve for

q

q

=

250.0

g

⋅

0.14

J

g

∘

C

⋅

(

62

−

10

)

∘

C

=

1820 J

I'll leave the answer rounded to two sig figs and expressed in kilojoules

q

=

1.8 kJ

Answer Explanation:

A substance's specific heat tells you how much heat is required to increase the mass of

1 g

of that substance by

1

∘

C

.

The equation that establishes a rel;ationship between heat absorbed and change in temperature looks like this

q

=

m

⋅

c

⋅

Δ

T

, where

q

- heat absorbed

m

- the mass of the sample

c

- the specific heat of the substance

Δ

T

- the change in temperature, defined as the difference between the final temperature and the initial temperature of the sample

You have all the information needed to find the amount of heat required to increase the temperature of your sample of mercury by that many degrees Celsius, so just rearange the above equation and solve for

q

q

=

250.0

g

⋅

0.14

J

g

∘

C

⋅

(

62

−

10

)

∘

C

=

1820 J

I'll leave the answer rounded to two sig figs and expressed in kilojoules

q

=

1.8 kJ

Answer link

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50 POINTS!
zysi [14]

<h3>No:1</h3>

The object is moving with constant or uniform acceleration and in average speed

<h3>No:-2</h3>

The object is de accelerating

<h3>No:-3</h3>

The object deaccelerated and came to rest so fast.

<h3>No:-4</h3>

The object moves slowly first then accelerated.

<h3>No:-5</h3>

The object accelerated at first so fast then move with constant acceleration then again accelerated .

7 0
2 years ago
An open-topped freight car with mass 24,000 kg is coasting without friction along a level track. It is raining very hard, and th
skelet666 [1.2K]

Answer:

(a) v = 3..6 m/s

(b) The rain falling downward has been able to affect the horizontal motion of the car by reducing it's velocity from 4 m/s to 3.6 m/s.

Explanation:

from the question we have the following:

mass of the car (Mc) = 24,000 kg

initial velocity of the car (u) = 4 m/s

mass of water (Mw) = 3000 kg

final velocity of the car (v) = ?

(a) we can calculate the final momentum of the car by applying the conservation of momentum where

initial momentum = final momentum

Mc x U = (Mc + Mw) x V

24000 x 4 = (24000 + 3000) x v

96,000 = 27000v

v =3.6 m/s

(b) The rain falling downward has been able to affect the horizontal motion of the car by reducing it's velocity from 4 m/s to 3.6 m/s.

7 0
3 years ago
Please answer all of these questions and you will get the brain list
pogonyaev

Answer:

1=900j

2=140j

3=5m

Explanation:

1,

work=force×displacement

w=450×2

w=900j

2,

w=f×s

w=70×2

w=140j

3,

w=f×s

200=40×s

200/40=s

s=5m

6 0
3 years ago
A box is lowered using a rope. If the acceleration of the box, is 3.3 m/s2 (downward) and its mass is 29.1 kg, what is the magni
Stells [14]

Answer:

T=189.15 N

Explanation:

As we know that for downward motion

F acting = F (weight) - Tension T

m a = mg - T

⇒ T = m (g - a)

T = 29.1 kg ( 9.8 m/s² - 3.3 m/s²)

T=189.15 N

8 0
3 years ago
When energy decreases, particle motion:<br> A. stops<br> B. increases<br> C. decreases
DaniilM [7]
C. decreases here you go
7 0
3 years ago
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