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Alexandra [31]
3 years ago
9

Which of the following statements is TRUE?

Physics
2 answers:
KIM [24]3 years ago
5 0
Hello there!

<span>Which of the following statements is TRUE?

Correct answer: </span>Light waves are electromagnetic waves and sound waves are mechanical waves.
VLD [36.1K]3 years ago
4 0
Both light waves are electromagnetic waves and sound waves are mechanical waves
brainliest pls
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d)through a railroad track

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How can you drop two eggs the fewest amount of times, without them breaking?
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Both eggs are identical. The aim is to find out the highest floor from which an egg will not break when dropped out of a window from that floor. If an egg is dropped and does not break, it is undamaged and can be dropped again. However, once an egg is broken, that's it for that egg.

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Please help me to do this problem
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we got time and velocity over time.

so the distance is again the area underneath the graph

for a triangle with known base and height it's

4*10 / 2

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3 years ago
An object appears red when viewed with white light. What color would it appear when viewed with blue light?
zvonat [6]

Answer:

Colour of any object is by the colour of light it reflects i.e if white light is incident on the object,it will reflect blue color.so it will appear blue.But if red light is incident on it,it will not reflect that and absorb it.so as it will not reflect any light it will appear black.

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7 0
3 years ago
Read 2 more answers
A non-ideal 12.2 V battery is connected across a resistor R. The internal resistance of the battery is 1.9Ohm. Calculate the pot
Brums [2.3K]

Answer:

R=100 Ohm, V=11.97 volts and I=0.12 amperes

R=10 Ohm, V=10.25 volts and I=1.20 amperes

R=2 Ohm, V=6.26 volts

Explanation:

The potential difference (voltage) of a battery with internal resistance is:

V=\xi-Ir (1)

with \xi the electromotive force (the voltage the batteries say to has) , I the current and r the internal resistance. By Ohm's law the current that passes through the resistor is:

I=\frac{V}{R} (2)

using (2) on (1):

V=\xi-\frac{V*r}{R}

solving for V:

V+\frac{V*r}{R}=\xi

V=\frac{\xi}{1+\frac{r}{R}} (3)

R=100 Ohm

V=\frac{12.2}{1+\frac{1.9}{100}}=11.97 V

R=10 Ohm

V=\frac{12.2}{1+\frac{1.9}{10}}=10.25 V

R=2 Ohm

V=\frac{12.2}{1+\frac{1.9}{2}}=6.26 V

Because we have now the values of I on the circuit (is the same through all the components because is a series circuit)

We use back substitution on (1) to find the current:

R=100 Ohm

I=\frac{V}{R}=\frac{11.97}{100}=0.12 A

R=10 Ohm

I=\frac{V}{R}=\frac{11.97}{10}=1.20 A

7 0
3 years ago
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