Question in incomplete, complete question is:
Technetium (Tc; Z = 43) is a synthetic element used as a radioactive tracer in medical studies. A Tc atom emits a beta particle (electron) with a kinetic energy (Ek) of
. What is the de Broglie wavelength of this electron (Ek = ½mv²)?
Answer:
is the de Broglie wavelength of this electron.
Explanation:
To calculate the wavelength of a particle, we use the equation given by De-Broglie's wavelength, which is:
![\lambda=\frac{h}{\sqrt{2mE_k}}](https://tex.z-dn.net/?f=%5Clambda%3D%5Cfrac%7Bh%7D%7B%5Csqrt%7B2mE_k%7D%7D)
where,
= De-Broglie's wavelength = ?
h = Planck's constant = ![6.624\times 10^{-34}Js](https://tex.z-dn.net/?f=6.624%5Ctimes%2010%5E%7B-34%7DJs)
m = mass of beta particle = ![9.1094\times 10^{-31} kg](https://tex.z-dn.net/?f=%209.1094%5Ctimes%2010%5E%7B-31%7D%20kg)
= kinetic energy of the particle = ![4.71\times 10^{-15}J](https://tex.z-dn.net/?f=4.71%5Ctimes%2010%5E%7B-15%7DJ)
Putting values in above equation, we get:
![\lambda =\frac{6.624\times 10^{-34}Js}{\sqrt{2\times 9.1094\times 10^{-31} kg\times 4.71\times 10^{-15}J}}](https://tex.z-dn.net/?f=%5Clambda%20%3D%5Cfrac%7B6.624%5Ctimes%2010%5E%7B-34%7DJs%7D%7B%5Csqrt%7B2%5Ctimes%209.1094%5Ctimes%2010%5E%7B-31%7D%20kg%5Ctimes%204.71%5Ctimes%2010%5E%7B-15%7DJ%7D%7D)
![\lambda = 6.762\times 10^{-12} m](https://tex.z-dn.net/?f=%5Clambda%20%3D%206.762%5Ctimes%2010%5E%7B-12%7D%20m)
is the de Broglie wavelength of this electron.
Balanced there are 2 Al, 6 oxygens on both sides.
Answer:
Explanation:
Efficiency of the electric power plant is ![e=1-\frac{T_{2}}{T_{1}}](https://tex.z-dn.net/?f=e%3D1-%5Cfrac%7BT_%7B2%7D%7D%7BT_%7B1%7D%7D)
Here Temperature of hot source ![T_{1} = 450^{o}C=450+273=723 K](https://tex.z-dn.net/?f=T_%7B1%7D%20%3D%20450%5E%7Bo%7DC%3D450%2B273%3D723%20K)
and Temperature of sink ![T_{1} = 20^{o}C=20+273=293 K](https://tex.z-dn.net/?f=T_%7B1%7D%20%3D%2020%5E%7Bo%7DC%3D20%2B273%3D293%20K)
Hence the efficiency is
Now another formula for thermal efficiency Is
![e_{therm}=\frac{Q_{1}-Q_{2}}{Q_{1}}=\frac{W}{Q_{1}}](https://tex.z-dn.net/?f=e_%7Btherm%7D%3D%5Cfrac%7BQ_%7B1%7D-Q_%7B2%7D%7D%7BQ_%7B1%7D%7D%3D%5Cfrac%7BW%7D%7BQ_%7B1%7D%7D)
Here QI is the of heat taken from source 100 MJ ; Q2 of heat transferred to the sink (river) to be found
W is the of work done and W = QI -Q2
Hence From![e_{therm}=\frac{Q_{1}-Q_{2}}{Q_{1}}=\frac{W}{Q_{1}}](https://tex.z-dn.net/?f=e_%7Btherm%7D%3D%5Cfrac%7BQ_%7B1%7D-Q_%7B2%7D%7D%7BQ_%7B1%7D%7D%3D%5Cfrac%7BW%7D%7BQ_%7B1%7D%7D)
![W=e(Q_{1})=(0.5947)(100)=59.47MJ](https://tex.z-dn.net/?f=W%3De%28Q_%7B1%7D%29%3D%280.5947%29%28100%29%3D59.47MJ)
Hence the of heat transferred to the river Is ![Q_{2} -W = (100 -59.47=40.53](https://tex.z-dn.net/?f=Q_%7B2%7D%20-W%20%3D%20%28100%20-59.47%3D40.53)
Answer:
The higher the frequency, the shorter the wavelength
Explanation:
All light waves move through a vacuum at the same speed, the number of wave crests passing by a given point in one second depends on the wavelength.
#1
- See H and C have shared their electrons so it's Covalent bonding
#2
Yes here we can see the dots and crosses clearly.
#3
It's Methane or CH_4
#4
There is no double bond