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Vera_Pavlovna [14]
3 years ago
11

HELP ASAP

Physics
2 answers:
MrRa [10]3 years ago
7 0
BURGER KING, MCDONALDS, PIZZA, CHIPOTLE
Anon25 [30]3 years ago
5 0
  • Relations
  • with respect to

Explanation:

Laws of Newton are

  • An object remains at its position of rest or motion until or unless any external force applied.
  • Force=Mass×Acceleration.
  • The initial momentum and final momentum remains same.
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6. If a bicyclist, with initial velocity of zero, steadily gained speed until reaching a final velocity of 39m/s, how far would
Bezzdna [24]

Answer:

  175 m

Explanation:

The average velocity for constant acceleration is the average of the beginning and ending velocities. That is (0+39)/2=19.5 m/s. If the bicyclist rides for 9 seconds, the distance traveled is ...

  (9 s)(19.5 m/s) = 175.5 m

She would travel 175.5 meters in that time.

7 0
4 years ago
PLEASE HELP ASAP
DaniilM [7]

Your answers:

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I'm sorry I cannot answer all your questions because there's a typing limit. :)

Thank you for your patience, and I hope I helped!

Would appreciate Brainliest ;)

4 0
3 years ago
An upward force of 18 N is applied via a string to lift a ball with a mass of 1.5 kg.
valentinak56 [21]

net force = applied force + gravity = 18N+(1.5kg)(-9.8m/s^2) = 3.3N

Force=mass times acceleration
acceleration=Force/mass
acceleration=3.3/1.5 m/s^2
acceleration=2.2m/s^s

7 0
3 years ago
A soccer ball is kicked from the ground with an initial speed v at an upward angle θ. A player a distance d away in the directio
Nady [450]

Answer:

The speed of player is given by

V=\frac{2v^{2} 2sin\alpha.cos\alpha-gd }{2vsin\alpha}

Explanation:

The time of flight for a projectile motion is given by

T=\frac{2vsin\alpha }{g}    (i)

where t is the time of flight, v is the initial speed, and α is the angle.

Now the person must also reach the impact point of ball in the same time as above.

Now the total distance D the player needs to cover is basically R horizontal range of projectile minus the distance d, range R is given by,

R=\frac{2v^{2} sin2\alpha }{g}

Now the distance the player must cover is given by

D= R-d

D= \frac{2v^{2} sin2\alpha }{g}  - d

 

D=\frac{2v^{2}sin2\alpha-gd}{g}  (ii)

Now the average speed of player is given by

V=\frac{D}{T}   (iii)

Replacing the values of D and T from eq. (i) and (ii) in eq. (iii).

V=\frac{\frac{2v^{2} sin2\alpha-gd }{g}}{\frac{2vsin\alpha }{g} }

V=\frac{2v^{2} 2sin\alpha.cos\alpha-gd }{2vsin\alpha}

3 0
3 years ago
A 90.0 kg person is sitting 1.00 m away from a 60.0 kg person at a football game. What is the gravitational force between them
Anton [14]

Answer:

<h2>The force is 36*10^-^9 N</h2>

Explanation:

According to newtons law on gravitation formula, which  we are going to apply,

F= \frac{Gm1m2}{d^2}

Where G represents universal gravitation constant, 6.67*10^-^1^1 N.m^2/kg^2

Given data

m1= 90 kg

m2= 60 kg

d= 1 m

Substituting our given data into the formula we have

F= \frac{6.67*10^-^1^1*90*60}{1^2}

F= \frac{6.67*10^-^1^1*5.4*10^3}{1^2}\\\\F= 36*10^-^9 N

5 0
4 years ago
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