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2 years ago

Is each ion stable? Explain.

Chemistry

1 answer:

jeka57 [31]2 years ago

5 0

Answer:

By satisfying the duet rule or the octet rule, ions are more stable.

Explanation:

Ionic bonds are formed through the exchange of valence electrons between atoms, typically a metal and a nonmetal. The loss or gain of valence electrons allows ions to obey the octet rule and become more stable.

The octet rule states that an atom is most stable when there are eight electrons in its valence shell. Atoms with less than eight electrons tend to satisfy the duet rule, having two electrons in their valence shell. By satisfying the duet rule or the octet rule, ions are more stable.

<em>I HOPE THIS HELPS!!!!</em>

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What mass of calcium chloride is produced from 5.59 mol of hydrochloric acid

svp [43]

From the mole ratio of the reaction as given in the equation of the reaction, the mass of calcium chloride that can be produced from 5.59 mol of hydrochloric acid is 310.245 g.

<h3>What mass of calcium chloride can be produced from 5.59 mol of hydrochloric acid?</h3>

The mass of calcium chloride that can be produced from 5.59 mol of hydrochloric acid is determined from the equation of the reaction.

The equation of the reaction is given below:

Ca²⁺ (aq) + 2 HCl (aq) ---> CaCl₂ (s) + H₂ (g)

From the equation of the reaction, the mole ratio of HCL and calcium chloride is 2 : 1

Therefore, moles of calcium chloride that can be produced will be:

The moles of calcium chloride = 5.59 moles * 1/2

The moles of calcium chloride = 2.795 moles

The mass of calcium chloride produced = moles * molar mass

Molar mass of calcium chloride = 111 g/mol

Mass of calcium chloride produced = 2.795 * 111

Mass of calcium chloride produced = 310.245 g

Learn more about mole ratio at: brainly.com/question/19099163

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1 year ago

Given the value of the equilibrium constant (Kc) for the equation (a), calculate the equilibrium constant for equation (b)

matrenka [14]

Answer: The value of equilibrium constant for new reaction is $1.92\times 10^{-25}$

Explanation:

The given chemical equation follows:

$O_2(g)\rightarrow \frac{2}{3}O_3(g)+\frac{1}{2}O_2(g)$

The equilibrium constant for the above equation is $5.77\times 10^{-9}$

We need to calculate the equilibrium constant for the equation of 3 times of the above chemical equation, which is:

$3O_2(g)\rightarrow 2O_3(g)$

The equilibrium constant for this reaction will be the cube of the initial reaction.

If the equation is multiplied by a factor of '3', the equilibrium constant of the new reaction will be the cube of the equilibrium constant of initial reaction.

The value of equilibrium constant for reverse reaction is:

$K_{eq}'=(5.77\times 10^{-9})^3=1.92\times 10^{-25}$

Hence, the value of equilibrium constant for new reaction is $1.92\times 10^{-25}$

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2 years ago