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3 years ago

What is the shortest day of the year known as? A.vernal B.equinox C.winter D.solstice summer solstice E.autumnal equinox

Chemistry

1 answer:

Olegator [25]3 years ago

3 0

Answer:

summer solstice

Explanation:

on june solstice the northen hemisphere leans more toward the sun giving us longer days and more strong sunlight and It's the opposite in the Southern Hemisphere where june marks the start of winter thus its the shortest day of the year

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A monoprotic weak acid, HA , dissociates in water according to the reaction:

Ratling [72]

Answer: The $pKa$ of the acid is 6.09

Explanation:

For the given chemical reaction:

$HA(aq.)\rightleftharpoons H^+(aq.)+A^-(aq.)$

The expression of equilibrium constant [tex[(K_a)[/tex] for the above equation follows:

$K_a=\frac{[H^+][A^-]}{[HA]}$

We are given:

$[HA]_{eq}=0.200M$

$[H^+]_{eq}=4.00\times 10^{-4}M$

$[A^-]_{eq}=4.00\times 10^{-4}M$

Putting values in above expression, we get:

$K_a=\frac{(4.00\times 10^{-4})\times (4.00\times 10^{-4}}{0.200}\\\\K_a=8.0\times 10^{-7}0$

p-function is defined as the negative logarithm of any concentration.

$pKa=-\log(K_a)$

So,

$pKa=-\log(8.0\times 10^{-7})\\\\pKa=6.09$

Hence, the $pKa$ of the acid is 6.09

7 0

3 years ago

What functional group is found in an alcohol?

Contact [7]

Answer:

an alcohol is a Hydroxyl group due to the OH~ that is associated with it's molecules

5 0

3 years ago

several of the flame tests were shades of red. what should be done in the laboratory to correctly identify one of these ions

yuradex [85]

You have to do another test to record the differences.

6 0

3 years ago

The molar heat capacity for carbon monoxide at constant volume is CV,m = 20.17 J/(K·mol). A 3.00-L fixed-volume flask contains C

kompoz [17]

ΔS = 0.250 J·K^(-1)

Step 1. Calculate the moles of CO

From the Ideal Gas Law,

n = (pV)/(RT) = (8.00 kPa × 3.00 L)/(8.314 kPa·L·K^(-1)·mol^(-1) × 298.15 K)

= 0.009 682 mol

ΔS = nC_Vln(T_2/T1)

= 0.0096 82 mol × 20.17 J·K^(-1)mol^(-1) ln(1073.15 K/298.15 K)

= 0.1953 J·K^(-1) × ln3.599 = 0.250 J·K^(-1)

5 0

4 years ago

1: Write balanced complete ionic equation for

monitta

Answer 1 : The balanced complete ionic equation will be,

$NaOH(aq)+HNO_3(aq)\rightarrow H_2O(l)+NaNO_3(aq)$

$Na^+(aq)+OH^-(aq)+H^+(aq)+NO_3^-(aq)\rightarrow H_2O(l)+Na^+(aq)+NO_3^-(aq)$

By removing the spectator ion in this equation, we get the balanced ionic equation.

$OH^-(aq)+H^+(aq)\rightarrow H_2O(l)$

Answer 2 : The balanced net ionic equation will be,

$2Na_3PO_4(aq)+3NiCl_2(aq)\rightarrow Ni_3(PO_4)_2(s)+6NaCl(aq)$

$6Na^+(aq)+2PO_4^{3-}(aq)+3Ni^+(aq)+6Cl^-(aq)\rightarrow Ni_3(PO_4)_2(s)+6Na^+(aq)+6Cl^-(aq)$

By removing the spectator ion in this equation, we get the balanced ionic equation.

$2PO_4^{3-}(aq)+3Ni^+(aq)\rightarrow Ni_3(PO_4)_2(s)$

Answer 3 : The balanced net ionic equation will be,

$2Na_3PO_4(aq)+3NiCl_2(aq)\rightarrow Ni_3(PO_4)_2(s)+6NaCl(aq)$

$6Na^+(aq)+2PO_4^{3-}(aq)+3Ni^+(aq)+6Cl^-(aq)\rightarrow Ni_3(PO_4)_2(s)+6Na^+(aq)+6Cl^-(aq)$

By removing the spectator ion in this equation, we get the balanced ionic equation.

$2PO_4^{3-}(aq)+3Ni^+(aq)\rightarrow Ni_3(PO_4)_2(s)$

Balanced equations : Balanced equations are the equations in which the number of individual elements present on the reactant side must be equal to the number of individual elements present on the product side.

Spectator ions : It is defined as the ions which do not participate in the chemical reaction. These ions exists in the same form on both the sides of the reaction.

7 0

3 years ago

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