Answer: 8.59 L of oxygen gas are needed to produce 100 kJ of energy at STP
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number
of particles.
Standard condition of temperature (STP) is 273 K and atmospheric pressure is 1 atmosphere respectively.
1 mole of every gas occupy volume at STP = 22.4 L
The balanced chemical reaction is:
![2C_6H_6(I)+15O_2(g)\rightarrow 12CO_2(g)+6H_2O(g)](https://tex.z-dn.net/?f=2C_6H_6%28I%29%2B15O_2%28g%29%5Crightarrow%2012CO_2%28g%29%2B6H_2O%28g%29)
3909.9 kJ of of energy is produced by = ![15\times 22.4=336L](https://tex.z-dn.net/?f=15%5Ctimes%2022.4%3D336L)
100 kJ of oxygen gas are needed to produce = ![\frac{336}{3909.9}\times 100=8.59L](https://tex.z-dn.net/?f=%5Cfrac%7B336%7D%7B3909.9%7D%5Ctimes%20100%3D8.59L)
Answer:
B
Explanation:
living things are not required to move
Answer:
1L
Explanation:
First, let us calculate the number of mole present in 20g of NaOH. This is illustrated below:
Mass = 20g
Molar Mass of NaOH = 23 + 16 + 1 = 40g/mol
Number of mole =?
Number of mole = Mass /Molar Mass
Number of mole of NaOH = 20/40 = 0.5mol
From the question given, we obtained the following data:
Molarity = 0.5M
Mole = 0.5mole
Volume =?
Molarity = mole /Volume
Volume = mole /Molarity
Volume = 0.5/0.5
Volume = 1L
Answer:
I assume your talking about carbon when you say 12 so it'd be 12 grams if you are
Explanation:
The molar mass of any substance in grams per mole is numerically equal to the mass of that substance expressed in atomic mass units.
Hope this helps you some
M/V=D
16.52/2.26=D
Density=6.86 g/cm^3