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shepuryov [24]
3 years ago
7

Chlorine is used to disinfect swimming pools. the accepted concentration for this purpose is 1.00 ppm chlorine, or 1.00 g of chl

orine per million grams of water. calculate the volume of a chlorine solution (in milliliters) a homeowner should add to her swimming pool if the solution contains 9.00 percent chlorine by mass and there are 2.29 × 104 gallons (gal) of water in the pool (1 gal = 3.79 l; density of liquids = 1.00 g/ml). enter your answer in scientific notation.
Chemistry
1 answer:
frez [133]3 years ago
6 0

The accepted concentration of chlorine is 1.00 ppm that is 1 gram of chlorine per million of water.

The volume of water is 2.29\times 10^{4} gal.

Since, 1 gal= 3785.41 mL

Thus, 2.29\times 10^{4} gal=2.29\times 10^{4}\times 3785.41 mL=8.66\times 10^{7}mL

Density of water is 1 g/mL thus, mass of water will be 8.66\times 10^{7}g.

Since, 1 grams of chlorine →10^{6} grams of water.

1 g of water →10^{-6} g of chlorine and,

8.66\times 10^{7}g of water →86.6 g of chlorine

Since, the solution is 9% chlorine by mass, the volume of solution will be:

V=\frac{100}{9}\times 86.6 mL=9.62\times 10^{2} mL

Thus, volume of chlorine solution is 9.62\times 10^{2} mL.

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As given:

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