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shepuryov [24]
3 years ago
7

Chlorine is used to disinfect swimming pools. the accepted concentration for this purpose is 1.00 ppm chlorine, or 1.00 g of chl

orine per million grams of water. calculate the volume of a chlorine solution (in milliliters) a homeowner should add to her swimming pool if the solution contains 9.00 percent chlorine by mass and there are 2.29 × 104 gallons (gal) of water in the pool (1 gal = 3.79 l; density of liquids = 1.00 g/ml). enter your answer in scientific notation.
Chemistry
1 answer:
frez [133]3 years ago
6 0

The accepted concentration of chlorine is 1.00 ppm that is 1 gram of chlorine per million of water.

The volume of water is 2.29\times 10^{4} gal.

Since, 1 gal= 3785.41 mL

Thus, 2.29\times 10^{4} gal=2.29\times 10^{4}\times 3785.41 mL=8.66\times 10^{7}mL

Density of water is 1 g/mL thus, mass of water will be 8.66\times 10^{7}g.

Since, 1 grams of chlorine →10^{6} grams of water.

1 g of water →10^{-6} g of chlorine and,

8.66\times 10^{7}g of water →86.6 g of chlorine

Since, the solution is 9% chlorine by mass, the volume of solution will be:

V=\frac{100}{9}\times 86.6 mL=9.62\times 10^{2} mL

Thus, volume of chlorine solution is 9.62\times 10^{2} mL.

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Calculate the average obtained from the following weighings of the same object. Do not forget to include formulas, units, and th
bazaltina [42]

Answer:

10.4376 g

Explanation:

First we <u>calculate the sum of the weighings</u>:

  • 10.4375 g + 10.4381 g + 10.4373 g + 10.4376 g = 41.7505 g

Then we <u>divide the sum by the number of weighings to calculate the average:</u>

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  • Average = Sum of weighings / Number of weighings
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6 0
2 years ago
For the following reaction, 4.07 grams of aluminum oxide are mixed with excess sulfuric acid. The reaction yields 10.4 grams of
torisob [31]

Answer:

Theoretical yield = 13.7 g

% yield =76 %

Explanation:

For Al_2O_3

Mass of Al_2O_3  = 4.07 g

Molar mass of Al_2O_3  = 101.96 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{4.07\ g}{101.96\ g/mol}

Moles\ of\ Al_2O_3= 0.0399\ mol

According to the reaction:

Al_2O_3+3H_2SO_4\rightarrow Al_2(SO_4)_3+3H_2O

1 mole of Al_2O_3  on reaction produces 1 mole of Al_2(SO_4)_3

So,  

0.0399 mole of Al_2O_3  on reaction produces 0.0399 mole of Al_2(SO_4)_3

Moles of Al_2(SO_4)_3  obtained = 0.0399 mole

Molar mass of Al_2(SO_4)_3 = 342.2 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

0.0399= \frac{Mass}{342.2\ g/mol}

Mass= 13.7\ g

<u>Theoretical yield = 13.7 g</u>

The expression for the calculation of the percentage yield for a chemical reaction is shown below as:-

\%\ yield =\frac {Experimental\ yield}{Theoretical\ yield}\times 100

Given , Values from the question:-

Theoretical yield = 13.7 g

Experimental yield = 10.4 g

Applying the values in the above expression as:-

\%\ yield =\frac{10.4}{13.7}\times 100

<u>% yield =76 %</u>

6 0
2 years ago
What are transferred in an oxidation-reduction reaction (1 point)?
madreJ [45]
electrons are transferred    in a oxidation-reduction  reaction

oxidation reduction  chemical equation involve  electrons  transfer   between  two species. In this reduction-oxidation type of chemical equation    oxidation  number of   molecule, atoms or ion  changes  by  gaining or losing  electrons,that is there  an oxidizing  agent and a  reducing agent  in the reaction.
7 0
3 years ago
Name any two polymers which are formed by the process of condensation polymerization.
ehidna [41]

Polyester and polyamide would be two synthetic polymers, created by condensation reaction.

5 0
3 years ago
The electron in a hydrogen atom can undergo a transition from n = 4 to n = 3, emitting a photon with energy 1.06 × 10 –19J. Use
konstantin123 [22]

Answer:

Wavelength (λ) = 1.875 × 10⁻⁶ m

Explanation:

Given:

Energy (e) =  1.06 × 10⁻¹⁹ J

Find:

Wavelength (λ) = ?

Computation:

e = hc / λ

λ = hc / e

where c = 3 × 10⁸

Planck's constant (h) = 6.625 × 10⁻³⁴

So,

Wavelength (λ) = (6.625 × 10⁻³⁴)(3 × 10⁸) / (1.06 × 10⁻¹⁹)

1. Wavelength (λ) = 1.875 × 10⁻⁶ m

2. Given n = 4 to n = 3 both are integer not fraction so, electron is quantize

5 0
3 years ago
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