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Free_Kalibri [48]
2 years ago
15

The KEOM tower across the street from West is approx. 155 meters high

Physics
1 answer:
blondinia [14]2 years ago
7 0

You told your insane friend that it will take the book 5.6 s to get to the ground.

From the question given above, the following data were obtained:

Height (H) = 155 m

<h3>Time (t) =? </h3>

<u>NOTE</u>: Acceleration due to gravity (g) = 10 m/s²

The time taken for the book to get to ground can be obtained as follow:

<h3>H = ½gt²</h3>

155 = ½ × 10 × t²

155 = 5 × t²

<h3>Divide both side by 5</h3>

t^{2}  = \frac{155}{5}\\\\

t² = 31

<h3>Take the square root of both side </h3>

t = \sqrt{31}

<h3>t = 5.6 s</h3>

Thus, the time taken for the book to get to the ground is 5.6 s

Hence, you told your insane friend that it will take the book 5.6 s to get to the ground.

Learn more: brainly.com/question/24903556

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Consider the motion of a 4.00-kg particle that moves with potential energy given by U(x) = + a) Suppose the particle is moving w
gtnhenbr [62]

Correct question:

Consider the motion of a 4.00-kg particle that moves with potential energy given by

U(x) = \frac{(2.0 Jm)}{x}+ \frac{(4.0 Jm^2)}{x^2}

a) Suppose the particle is moving with a speed of 3.00 m/s when it is located at x = 1.00 m. What is the speed of the object when it is located at x = 5.00 m?

b) What is the magnitude of the force on the 4.00-kg particle when it is located at x = 5.00 m?

Answer:

a) 3.33 m/s

b) 0.016 N

Explanation:

a) given:

V = 3.00 m/s

x1 = 1.00 m

x = 5.00

u(x) = \frac{-2}{x} + \frac{4}{x^2}

At x = 1.00 m

u(1) = \frac{-2}{1} + \frac{4}{1^2}

= 4J

Kinetic energy = (1/2)mv²

= \frac{1}{2} * 4(3)^2

= 18J

Total energy will be =

4J + 18J = 22J

At x = 5

u(5) = \frac{-2}{5} + \frac{4}{5^2}

= \frac{4-10}{25} = \frac{-6}{25} J

= -0.24J

Kinetic energy =

\frac{1}{2} * 4Vf^2

= 2Vf²

Total energy =

2Vf² - 0.024

Using conservation of energy,

Initial total energy = final total energy

22 = 2Vf² - 0.24

Vf² = (22+0.24) / 2

Vf = \sqrt{frac{22.4}{2}

= 3.33 m/s

b) magnitude of force when x = 5.0m

u(x) = \frac{-2}{x} + \frac{4}{x^2}

\frac{-du(x)}{dx} = \frac{-d}{dx} [\frac{-2}{x}+ \frac{4}{x^2}

= \frac{2}{x^2} - \frac{8}{x^3}

At x = 5.0 m

\frac{2}{5^2} - \frac{8}{5^3}

F = \frac{2}{25} - \frac{8}{125}

= 0.016N

8 0
3 years ago
what device is made of coils of wire with an electrical current passing through it in order to generate a magnetic field
Umnica [9.8K]

Transformer

<u>Explanation:</u>

A transformer is a device with two or more magnetically coupled windings. A time varying current in one coil (primary winding) generates a magnetic field which induces a voltage in the other coil (secondary winding). Transformers are capable of either increasing or decreasing the voltage and current levels of their supply, without modifying its frequency, or the amount of electrical power being transferred from one winding to another via the magnetic circuit. There are two types of transformer:

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Why do intrusive igneous rocks have large crystals?
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3 years ago
How many ways can motion change
meriva

Answer:

There are four main ways of doing that :-

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  • Acceleration
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Hope it helps!

7 0
3 years ago
Read 2 more answers
In this circuit the battery provides 3 V, the resistance R1 is 7 Ω, and R2 is 5 Ω. What is the current through resistor R2? Give
sveta [45]

Answer:

The current pass the R_2 is  I  = 0.25 A

Explanation:

The diagram for this question is shown on the first uploaded image  

From the question we are told that

    The voltage  is  V =  3V

     The first resistance is  R_1 = 7 \Omega

     The second resistance is  R_2 = 5 \Omega

Since the resistors are connected in series their equivalent resistance is  

       R_{eq} =  R_1 +R_2

Substituting values

         R_{eq} = 7 + 5

         R_{eq} = 12 \Omega

Since the resistance are connected in serie the current passing through the circuit  is the same current passing through R_2 which is mathematically evaluated as

        I  =  \frac{V}{R_{eq}}

Substituting values  

      I  =  \frac{3}{12}

      I  = 0.25 A

3 0
3 years ago
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