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Free_Kalibri [48]
2 years ago
15

The KEOM tower across the street from West is approx. 155 meters high

Physics
1 answer:
blondinia [14]2 years ago
7 0

You told your insane friend that it will take the book 5.6 s to get to the ground.

From the question given above, the following data were obtained:

Height (H) = 155 m

<h3>Time (t) =? </h3>

<u>NOTE</u>: Acceleration due to gravity (g) = 10 m/s²

The time taken for the book to get to ground can be obtained as follow:

<h3>H = ½gt²</h3>

155 = ½ × 10 × t²

155 = 5 × t²

<h3>Divide both side by 5</h3>

t^{2}  = \frac{155}{5}\\\\

t² = 31

<h3>Take the square root of both side </h3>

t = \sqrt{31}

<h3>t = 5.6 s</h3>

Thus, the time taken for the book to get to the ground is 5.6 s

Hence, you told your insane friend that it will take the book 5.6 s to get to the ground.

Learn more: brainly.com/question/24903556

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Answer:

<em>11.06m/s²</em>

Explanation:

According to Newtons second law of motion

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Given

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theta = 36 degrees

g = 9.8m/s²

a is the acceleration

Substitute

208 - 0.148(17)(9.8)cos 36 = 17a

208 - 24.6568cos36 = 17a

208 - 19.9478 = 17a

188.05 = 17a

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3 years ago
A 1.53-kg bucket hangs on a rope wrapped around a pulley of mass 7.07 kg and radius 66 cm. This pulley is frictionless in its ax
levacccp [35]

Answer:

\alpha = 6.431\,\frac{rad}{s^{2}}

Explanation:

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Given that tension is equal to the weight of the bucket, the angular acceleration experimented by the pulley is:

T = \frac{1}{2}\cdot M \cdot R \cdot \alpha

m_{b}\cdot g = \frac{1}{2}\cdot M \cdot R \cdot \alpha

\alpha = \frac{2\cdot m_{b}\cdot g}{M\cdot R}

\alpha = \frac{2\cdot (1.53\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}{(7.07\,kg)\cdot (0.66\,m)}

\alpha = 6.431\,\frac{rad}{s^{2}}

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