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2 years ago

The KEOM tower across the street from West is approx. 155 meters high

Physics

1 answer:

blondinia [14]2 years ago

7 0

You told your insane friend that it will take the book 5.6 s to get to the ground.

From the question given above, the following data were obtained:

Height (H) = 155 m

<u>NOTE</u>: Acceleration due to gravity (g) = 10 m/s²

The time taken for the book to get to ground can be obtained as follow:

155 = ½ × 10 × t²

155 = 5 × t²

<h3>Divide both side by 5</h3>

$t^{2} = \frac{155}{5}\\\\$

t² = 31

<h3>Take the square root of both side </h3>

$t = \sqrt{31}$

Thus, the time taken for the book to get to the ground is 5.6 s

Hence, you told your insane friend that it will take the book 5.6 s to get to the ground.

Learn more: brainly.com/question/24903556

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Answer:

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The electric force between charges can be determined by;

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= 2q x $\frac{q}{3}$ x $\frac{k}{r^{2} }$

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The electric force between the given charges would change by $\frac{2}{3}$ .

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Explanation:

Given that,

Charge 1, $q_1=-5.45\times 10^{-6}\ C$

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1. The electric force is given by :

$F=k\dfrac{q_1q_2}{r^2}$

$F=9\times 10^9\times \dfrac{-5.45\times 10^{-6}\times 4.39\times 10^{-6}}{(0.0209)^2}$

F = -492.95 N

2. Distance between two identical charges, $r=0.0209\ m$

Electric force is given by :

$F=\dfrac{kq_3^2}{r^2}$

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