Answer:
work done = 117 kJ
Explanation:
given data
mass m = 3 kg
constant pressure P = 200 kPa
temperature T = 200°C
solution
we know that work done by steam is express as
work done = pressure × ΔVolume ....................1
and here ΔVolume = final volume - initial volume
we use here steam table and get at pressure 200 kPa
final specific volume = 1.08052 m³/kg
and
initial specific volume = 0.885735 m³/kg
so here
ΔV = 3 × (1.08052 - 0.885735)
ΔV = 0.584 m³
so put value in equation 1 we get
work done by steam = 200 × 0.584
work done = 117 kJ
Answer:
Explanation:
We can start from the known formula:
so we can write, since we want the initial velocity in terms of the ball's displacement, its acceleration in the vertical direction, and the elapsed time:
and for our values we have:
Answer: The temperature increases on the stratosphere with the altitude, given that absorption of the ultraviolet rays by the ozone.
Explanation: On the stratosphere, the water vapor and the umidity are almost nonexistents and, in view of the absorption of ultraviolet rays by the ozon, the temperature increases, reaching 35,6º Fahrenheit.
The ozone is a unusual type of oxygen molecule. In the stratosphere, the ozone appears on a large scale and warms it up by the absorption of the ultraviolet rays energy.
Answer:
Esses movimentos são movimentos naturais.
Explicação:
Se uma pedra cair do topo de um telhado ou edifício, a pedra se moverá em direção à terra, enquanto a fumaça produzida devido à queima da madeira vai para cima, então de acordo com Aristosteles esses tipos de movimento são chamados de movimento natural porque de acordo à definição de movimento natural que não requer nenhuma força, então esses dois movimentos também se movem na direção para baixo e para cima sem usar qualquer força, então podemos dizer que esses movimentos são naturais.
niAnswer:
(A) Vx = -9.14ωCosωt,
Vy = 9.14ωSinωt
(B) ax =9.14ω²Sinωt,
ay = 9.14ω²Cosωt
Explanation:
The velocity of a body ia the time derivative of the poaition function of the body with respect to time. Given equations x = −9.14 sin ωt and y = 4.00 − 9.14 cos ωt,
All we need to do to get the velocity is to differentiate each of the equation above with respect to time in order to get Vx and Vy required of us.
Vx = dx/dt = -9.14ωCosωt and
Vy = dy/dt = 9.14ωSinωt
In order to get the acceleration we differentiate the velocity function with respect to time. That is,
A = dv/dt
ax = dVx/dt = 9.14ω²Sinωt
ay = dVx/dt = 9.14ω²Cosωt