Question

1)How fast is a ball moving when falling from rest and hits the ground 1.70 seconds later?

Answer 1

The final velocity of the ball is16.66 m/s.

Given the following data:

• Initial velocity, U = 0 m/s (since the ball is falling from rest).

• Time, t = 1.70 seconds.

We know that acceleration due to gravity (a) for a ball in free fall is equal to 9.8 meter per seconds square.

To find how fast (velocity) the ball is moving, we would use the first equation of motion:

Mathematically, the first equation of motion is calculated by using the formula;

$V = U + at$

Where:

• V is the final velocity.

• U is the initial velocity.

• a is the acceleration.

• t is the time measured in seconds.

Substituting the given parameters into the formula, we have;

$V = 0 + 9.8(1.7)$

$V = 9.8$ × $1.70$

Final velocity, V = 16.66 m/s.

Therefore, the final velocity of the ball is16.66 m/s.

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