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Lubov Fominskaja [6]
3 years ago
5

How to do this goalookr goalookr

Engineering
1 answer:
Zepler [3.9K]3 years ago
7 0

Well, I am not able to understand your question...

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Why is the contractor normally required to submit a bid bond when making a proposal to an owner on a competitively bid contract?
just olya [345]

Answer:

It serves as a guarantee that the contractor who wins the bid will honor the terms of the bid after the contract is signed.

Explanation:

A bid bond is a type of construction bond that protects the obligee in a  construction bidding process.

A bid bond typically involves three parties:

The obligee; the owner or developer of the construction project under bid. The principal; the bidder or proposed contractor.

The surety; the agency that issues the bid bond to the principal example insurance company or bank.

A bid bond generally serves as a guarantee that the contractor who wins the bid will honor the terms of the bid after the contract is signed.

3 0
3 years ago
An engineer who invested very well plans to retire now because she has $2,000,000 in her ORP account. How long will she be able
Ede4ka [16]

Answer:

20 years

Explanation:

You do 2,000,000 ÷ 100,000 but you can simplify that to 20 ÷ 1 = 20

During those 20 years, the profits you earn will be 80,000 since when you do 2,000,000 x 0.04 but you can simplify that to 20,000 x 4 getting 80,000 and that quite doesn't reach 100,000 dollars

8 0
3 years ago
In the 1960s through 1980s, a medical filter manufacturer in Ann Arbor discharged 1,4-dioxane (an industrial solvent) directly i
stepladder [879]

Answer:

<u>Option-</u> C

  • In the 1960s through 1980s, a medical filter manufacturer in Ann Arbor discharged 1,4-dioxane (an industrial solvent) directly into the environment, where it ultimately leached into underlying groundwater aquifers. A plume of 1,4-dioxane has been spreading under Ann Arbor and could pose water quality risks if it reaches Barton Pond, which supplies 85% of the city's drinking water. So, we can evaluate the given information by concluding that the  EPA classifies 1,4-dioxane as a probable carcinogen with a potency factor of 0.011 (mg/kg/d)1. If the water contains the EPA's allowable limit of 7.2 μg/L of 1,4-dioxane, calculate the carcinogenic risk based on the default EPA exposure factors over a lifetime for ingestion of potable water in an average adult. Is the water safe to drink based on the "rule of thumb" discussed in class?                                      

5 0
3 years ago
Now write a mechanism for the first step of the reaction leading to the major product. In your mechanism show, with curved arrow
MrRa [10]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The solution is shown on the second, third ,fourth

Explanation:

The explanation is shown on the second, third image

3 0
4 years ago
transformer has 26 turns on the primary coil and 720 turns on the secondary coil. If this transformer is to produce an output of
hram777 [196]
<h2>Corrected Question:</h2>

A step-up transformer has 26 turns on the primary coil and 720 turns on the secondary coil. If this transformer is to produce an output of 4100 V with a 16-mA current, what input current and voltage are needed?

<h2>Answer:</h2>

The input current and voltage needed are 443 mA and 148 V respectively.

<h2>Explanation:</h2>

In a step-up transformer, the relationship between the number of turns in its primary coil (N_{p}), the number of turns in its secondary coil (N_{s}), the input voltage (V_{p}), the output voltage (V_{s}), the input current (I_{p}), and the output current (I_{s}) is given by;

\frac{N_{s} }{N_{p} } = \frac{V_{s} }{V_{p} } = \frac{I_{p} }{I_{s} }

This implies that;

\frac{N_{s} }{N_{p} } = \frac{V_{s} }{V_{p} }  ---------------------(i)

\frac{N_{s} }{N_{p} } = \frac{I_{p} }{I_{s} }  ---------------------(ii)

From the question;

N_{p} = 26 turns

N_{s} = 720 turns

V_{s} = 4100V

I_{s} = 16mA = 16 x 10⁻³A

(a) Substitute these values into equation (ii) as follows;

\frac{720}{26} = \frac{I_{p} }{16*10^{-3}}

Solve for I_{p};

I_{p} = 720 x 16 x 10⁻³ / 26

I_{p} = 443 x 10⁻³

I_{p} = 443 mA

Therefore the input current needed is 443mA

(b) Also, substitute those values into equation (i) as follows;

\frac{720}{26} = \frac{4100 }{V_{p} }

Solve for V_{p};

V_{p} = 4100 x 26 / 720

V_{p} = 148 V

Therefore, the input current needed is 148 V

5 0
3 years ago
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