Answer:
11.3298W
Explanation:
The rate of heat transfer is determined from the enthalpy of vaporization at the give pressure obtained and the mass flow rate. The mass flow rate is determined from the volume of the boiled water, the given time interval and the specific volume of the saturated liquid.
Given that
1atm as the atmospheric pressure
Internal diameter = 20cm = 0.2m
Time = 15mins = (15×60)secs
Latent heat of vaporization (hevap) = 2256.6
Q = mh(evap)
= m/∆t . hevap
= V/αliq∆t ×h(evap)
D^2π∆h/4αliq ∆t × hevap
= 0.2^2 ×π×0.8×2256.5/4×0.001043×15×60
=0.04×3.142×0.08×2256.6/2.00256
= 22.68876/2.00256
Q = 11.3298W
Answer:
true cuase it is true its not false
Answer:
The minimum angular spread of the laser beam is 3.32 × radians (or 3.32 μrad).
Explanation:
The minimum angular spread of a wave is the ratio of its narrowest diameter to its wavelength.
From Rayleigh's formula,
Angular spread = 1.22 (wavelength ÷ diameter)
= 1.22 (λ ÷ D)
Given that:
diameter, D = 0.18 m and wavelength, λ = 490 nm, then;
Angular spread of the laser beam = 1.22 (λ ÷ D)
= 1.22
= 1.22× 2.7222 ×
= 3.3211 × rad
The minimum angular spread of the laser beam is 3.32 × radians.
Answer: 2,464m
Explanation:
Echo made by a source is dependent on the velocity of the sound in air/water, the distance between the source and the reflector and the time taken
Using the echo formula
2x = vt
Where x is the distance between the source and the reflector
v is the velocity of the sound in sea water is approximately= 1540m/s (This varies from place to place and depending on the season and nature of water)
t is the time taken
t = 3.20s
Substituting this datas into the equation to get 'x'
2x = 1540 × 3.20
x = 1540×3.20/2
x = 2,464m
The distance between the object creating the echo is 2,464m