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3 years ago

How do gas laws predict absolute zero?

Chemistry

2 answers:

UNO [17]3 years ago

3 0

Answer:

If a gas contracts by 1/273 of its volume for each degree of cooling, it should contract to zero volume at a temperature of –273°C; this is the lowest possible temperature in the universe, known as absolute zero.It appeared that an “ideal gas” at constant pressure would reach zero volume at what is now called the absolute zero of temperature. Any real gas actually condenses to a liquid or a solid at some temperature higher than absolute zero. Therefore, the ideal gas law is only an approximation to real gas behaviour.

Leokris [45]3 years ago

3 0

"If a gas contracts by 1/273 of its volume for each degree of cooling, it should contract to zero volume at a temperature of –273°C; this is the lowest possible temperature in the universe, known as absolute zero."

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MrRa [10]

Answer:

2h+02=h20

Explanation:

2 in front of h on left side

2 in front of h on right side

3 0

3 years ago

Read 2 more answers

The following three equations represent reactions done in this lab exercise. Classify each reaction by their type. Note there ma

gulaghasi [49]

Answer: 1. $Cu(s)+4HNO_3(aq)rightarrow Cu(NO_3)_2(aq)+2NO_2(g)+2H_2O(l)$ : oxidation reduction

2. $Cu(NO_3)_2(aq)+2NaOH(aq)\rightarrow Cu(OH)_2(s)+2NaNO_3(aq)$ : precipitation

3. $CuO(s)+2HCl(aq)\rightarrow CuCl_2(aq)+H_2O(l)$ : Double displacement

Explanation:

Oxidation-reduction reaction or redox reaction is defined as the reaction in which oxidation and reduction reactions occur simultaneously.

Oxidation reaction is defined as the reaction in which a substance looses its electrons. The oxidation state of the substance increases.Reduction reaction is defined as the reaction in which a substance gains electrons. The oxidation state of the substance gets reduced.

$Cu(s)+4HNO_3(aq)rightarrow Cu(NO_3)_2(aq)+2NO_2(g)+2H_2O(l)$

Double displacement reaction is defined as the reaction where exchange of ions takes place. Double displacement reaction in which one of the product remain in solid form are represented by (s) after their chemical formulas. Such double displacement reaction are called as precipitation reaction.

$Cu(NO_3)_2(aq)+2NaOH(aq)\rightarrow Cu(OH)_2(s)+2NaNO_3(aq)$

Double displacement reaction is defined as the reaction where exchange of ions takes place.

$CuO(s)+2HCl(aq)\rightarrow CuCl_2(aq)+H_2O(l)$

Single displacement reaction is defined as the reaction where more reactive element displaces a less reactive element from its chemical reaction.

Decomposition reaction is defined as the reaction where a single substance breaks down into two or more simpler substances.

Synthesis/Combination reaction is defined as the reaction where substances combine in their elemental state to form a single compound.

6 0

3 years ago

a compound is 21.20% nitrogen,6.06% hydrogen, 24,30% sulfur, and 48.45% oxygen. write the empirical formula and name the compoun

IRISSAK [1]

The numbers may be off by a few, if you worked it out, since my periodic table is for AP chemistry. Hope this helps!!!

4 0

4 years ago

Answer this ASAP please!! Question: How many magnesium atoms does magnesium oxide need? (Science) (ONLY ANSWER IF YOU KNOW WHAT

aliina [53]

Answer:

40.3 for the unit that represents the minimum amount of magnesium oxide I beilieve.

Explanation:

Magnesium atoms are heavier than oxygen atoms, so we expect more than 50% of magnesium in the weight composition. Taking just one atom of Mg and one atom of O you will get a mass of 16.0 + 24.3 = 40.3.

Hope this helps! Please tell me if you have any questions :))

7 0

3 years ago

A sample of methane gas has a volume of 10 l at a pressure of 1.5 atm and a temperature of 20 °c. what volume does the gas occup

a_sh-v [17]

We can use combined gas laws to solve for the volume of the gas
$\frac{PV}{T}$
where P - pressure, V - volume , T - temperature and k - constant
$\frac{P1V1}{T1} = \frac{P2V2}{T2}$
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
T1 - temperature in Kelvin - 20 °C + 273 = 293 K
T2 - 40 °C + 273 = 313 K
substituting the values
$\frac{1.5 atm*10L}{293 K} = \frac{0.9 atm*V}{313K}$
V = 17.8 L
volume of the gas is 17.8 L

7 0

3 years ago