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3 years ago

Balancing Equations. How many of the element should I drag to the center?

Chemistry

1 answer:

babunello [35]3 years ago

8 0

Answer:

4FeS + 7O₂ ----> 2Fe₂O₃ + 4SO₂

Explanation:

You have to drag the elements shown on the right under the formula. For example, you would have to drag 4 of the FeS molecules under the 4FeS text in the formula. Then place 7 O₂ molecules under the 7O₂ text, etc.

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Lowering an object decrease is potential

Tresset [83]

Answer:

Lowering the object near the ground decreases its potential energy.

Explanation:

Potential Energy : Energy possessed by the object due to its shape ,Size and Position is called potential energy.

Example :

Change in shape and size : When you compress the spring , potential energy is introduced in it . So it expand quickly when you remove your hand.

Change in position : when you swing , after attaining maximum height (extreme ends) , the swing comes back on its on .This is because at maximum height ,the swing has maximum Potential energy . Hence it fall back on its on because it already has potential energy.

Potential energy(P) is given by the formula :

P = mgh

where ,

m= mass of the object

g = acceleration due to gravity

h = height of the object from the ground

If the height of the object increases from the ground , its potential energy also get increase.

On lowering the object The height of the object from the ground reduces . So potential energy also reduces.

8 0

3 years ago

Urea, (NH2)2CO, is a product of metabolism of proteins. An aqueous solution is 37.2% urea by mass and has a density of 1.032 g/m

Feliz [49]

Answer:

The molarity of urea in this solution is 6.39 M.

Explanation:

Molarity (M) is the number of moles of solute in 1 L of solution; that is

$molarity = moles of solute ÷ liters of solution$

To calculate the molality, we need to know the number of moles of urea and the volume of solution in liters. We assume 100 grams of solution.

Our first step is to calculate the moles of urea in 100 grams of the solution,

using the molar mass a conversion factor. The total moles of 100g of a 37.2 percent by mass solution is

60.06 g/mol ÷ 37.2 g = 0.619 mol

Now we need to calculate the volume of 100 grams of solution, and we use density as a conversion factor.

1.032 g/mL ÷ 100 g = 96.9 mL

This solution contains 0.619 moles of urea in 96.9 mL of solution. To express it in molarity, we need to calculate the moles present in 1000 mL (1 L) of the solution.

0.619 mol/96.9 mL × 1000 mL= 6.39 M

Therefore, the molarity of the solution is 6.39 M.

4 0

3 years ago

What mass of Cu(s) is electroplated by running 24.5A of current through a Cu2+(aq)solution for 4.00 h?Express your answer to thr

Masja [62]

Answer: 116 g of copper

Explanation:

$Q=I\times t$

where Q= quantity of electricity in coloumbs

I = current in amperes = 24.5A

t= time in seconds = 4.00 hr = $4.00\times 3600s=14400s$ (1hr=3600s)

$Q=24.5A\times 14400s=352800C$

$Cu^{2+}+2e^-\rightarrow Cu$

$2\times 96500C=193000C$ of electricity deposits 63.5 g of copper.

352800 C of electricity deposits = $\frac{63.5}{193000}\times 352800=116g$ of copper.

Thus 116 g of Cu(s) is electroplated by running 24.5A of current

Thus remaining in solution = (0.1-0.003)=0.097moles

8 0

3 years ago

How many electrons will be found in the “p” orbitals in the ground state of chlorine atom?

emmasim [6.3K]

Chlorine, Cl , is located in period 3, group 17 of the periodic table, and has an atomic number equal to 17 . This tells you that a neutral chlorine atom will have a total of 17 electrons surrounding its nucleus. Now, notice that the first energy level doesn't not contain a p-subshell,

7 0

3 years ago

Given a 0.200 M solution of anserine at its isoelectric point and ready access to 0.100 M HCl, 0.100 M NaOH and distilled water,

vekshin1

Solution :

Given :

Amount of anserine solution = 0.200 M

pH value is = 7.20

Preparation of 0.04 M solution of anserine from the 0.2 M solution.

0.2 M x $x$ = 0.04 M x 1000 ml

$x$ = 200 ml

So the 200 ml of 0.2 M anserine solution is required to prepare0.04 M of anserine.

0.1 M x $x$ = 0.04 x 1000 ml

$x$ = 400 ml

Therefore, 400 ml of HCl is needed.

6 0

3 years ago