Explanation:
It is given that,
Number of turns in primary coil, 
Number of turns in secondary coil, 
Voltage in primary coil, 
Current in primary coil, 
We have to find the voltage and current in the secondary coli. Firstly calculating the voltage in secondary coil as :
Now, calculating the current present in the secondary coil as :
<em>Hence, this is the required solution.</em>
The velocity is changing.
Answer: 1.59 sec
Explanation:
The kinetic energy contained in the rotation of the cylinder is 1/2 m v^2
The kinetic energy of translation is also 1/2 m v^2
so the total energy is m v^2
The force applied is mg sin (theta)
= m x 9.8 x 1/2
= 4.9 m
Now equate
F x d = m v^2
4.9 m x 3.1 = m v^2
v^2 = 4.9 x 3.1
v = sqrt(4.9 x 3.1) = 3.9 m/s
Acceleration.
V^2 = 2 a s
4.9 x 3.1 = 2 x a x 3.1
4.9 = 2 a
a = 2.45 m/s^2
Time
T = v/a
= 3.9/2.45
= 1.59 sec
A :-) F = mv^2 by t
Given - m = 10 kg
r = 10 m
v = 10 m/s
Solution -
F = mv^2 by t
F = 10 x 10^2 by 10
F = 10 x 100 by 10
( cut 10 and 10 because 10 x 1 = 10 )
F = 100 N
.:. The centripetal force is 100 N
D all of the above
Hope it helps
