Explanation:
Given that,
The pilot directs the aircraft to fly due north at 600km/h.
A side-wind blows at 100km/h towards the east.
We need to find the aircraft's resultant velocity. et it be v. It can be calculated as follows :
For direction,
So, the aircraft's resultant velocity is 608.27 km/h and it is at and angle of 80.53°.
Answer:
a. 120 W
b. 28.8 N
Explanation:
To a good approximate, the only external force that does work on a cyclist moving on level ground is the force of air resistance. Suppose a cyclist is traveling at 15 km/h on level ground. Assume he is using 480 W of metabolic power.
a. Estimate the amount of power he uses for forward motion.
b. How much force must he exert to overcome the force of air resistance?
(a)
He is 25% efficient, therefore the cyclist will be expending 25% of his power to drive the bicycle forward
Power = efficiency X metabolic power
= 0.25 X 480
= 120 W
(b)
power if force times the velocity
P = Fv
convert 15 km/h to m/s
v = 15 kmph = 4.166 m/s
F = P/v
= 120/4.166
= 28.8 N
definition of terms
power is the rate at which work is done
force is that which changes a body's state of rest or uniform motion in a straight line
velocity is the change in displacement per unit time.
A. 320 g
B. 160 g
C. 80 g
D. 40 g
Answer:
<u><em>First Reaction:</em></u>
=> 
<u><em>Second Reaction:</em></u>
=> 
<u><em>Combined Reaction:</em></u>
=> 
Answer:<em> </em><em>1.04 × 10¹⁶ photons</em>
Explanation:
1) Data:
- E = 3.85mJj (mili joules) = 3.85×10⁻³ J
- λ = 532 nm = 532 × 10⁻⁹ m
2) Physical principles
a) The energy of a photon is given by the equation E = hν.
Where:
- h is Planck's constant 6.62607004 × 10⁻³⁴ J×s
- ν is the freguency of the light
b) The wavelength, λ, and the frequency, are related by the equation:
- ν = c / λ, where c is the speed of light at vacuum, approximately 3.0 × 10⁸ m/s
3) Solution:
- ν = c / λ = 3.0 × 10⁸ m/s / (538 nm) × 10⁹ nm/m = 5.576×10¹⁴ Hz
- E = hν = 6.62607004 × 10⁻³⁴ J×s s × 5.576×10¹⁴ Hz = 3.69 × 10 ⁻¹⁹ J
- Divide the total energy by the energy of one photon to find the number of photons:
3.85×10⁻³ J / 3.69 × 10 ⁻¹⁹ J-photon = 1.04 × 10¹⁶ photons ← answer
