A becuz its at da it dont got no wa
The distance is 30 km and the displacement is 22.4 km North East
Answer:


Explanation:
<u>Displacement
</u>
It's a vector magnitude that measures the space traveled by a particle between an initial and a final position. The total displacement can be obtained by adding the vectors of each individual displacement. In the case of two displacements:

Given a vector as its polar coordinates (r,\theta), the corresponding rectangular coordinates are computed with


And the vector is expressed as

The monkey first makes a displacement given by (0.198 km,0°). The angle is 0 because it goes to the East, the zero-reference for angles. Thus the first displacement is

The second move is (145 m , -15.8°). The angle is negative because it points South of East. The second displacement is

The total displacement is


In (magnitude,angle) form:



