1.

Label the figure below with the names of a volcano's parts.

nexus9112 [7]

Answer:

Hello the answer for the volcanos is here below:

7. Pipe

8. Crater

9. Vent

10. lava flow

11. magma chamber

Hope this helps :)

4 0

1 year ago

The center on your school’s basketball team is 6 ft 10 in tall. How tall is the player in millimeters (mm)?

svp [43]

The answer is 6 ft 10 inches in millimeters (mm) is 0.833 ft.

Given,

The center of the school's basketball team is 6 ft 10 inches tall.

We have to convert the height of the player from feet and inches to feet.

Using the conversion factor,

1 ft = 12 inches

or, 12inches/ 1 ft

Converting 6ft 10 inches to ft, we get;

10 inches × 1 ft/ 12inches

= 0.833 ft

Therefore 6 ft 10 inches in millimeters (mm) is 0.833 ft.

Unit conversion is a method in which we multiply or divide with a particular numerical factor and then finally round off to the nearest significant digits.

To learn more about Millimeter and Unit conversions, visit: brainly.com/question/26371870

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5 0

1 year ago

What type of bonding is found in the compound of2?

Ratling [72]

Answer:

chemical bond

Explanation:

because atom can join together by forming a chemical bond

7 0

3 years ago

Suppose of copper(II) acetate is dissolved in of a aqueous solution of sodium chromate. Calculate the final molarity of acetate

uranmaximum [27]

Answer:

0.0714 M for the given variables

Explanation:

The question is missing some data, but one of the original questions regarding this problem provides the following data:

Mass of copper(II) acetate: $m_{(AcO)_2Cu} = 0.972 g$

Volume of the sodium chromate solution: $V_{Na_2CrO_4} = 150.0 mL$

Molarity of the sodium chromate solution: $c_{Na_2CrO_4} = 0.0400 M$

Now, when copper(II) acetate reacts with sodium chromate, an insoluble copper(II) chromate is formed:

$(CH_3COO)_2Cu (aq) + Na_2CrO_4 (aq)\rightarrow 2 CH_3COONa (aq) + CuCrO_4 (s)$

Find moles of each reactant. or copper(II) acetate, divide its mass by the molar mass:

$n_{(AcO)_2Cu} = \frac{0.972 g}{181.63 g/mol} = 0.0053515 mol$

Moles of the sodium chromate solution would be found by multiplying its volume by molarity:

$n_{Na_2CrO_4} = 0.0400 M\cdot 0.1500 L = 0.00600 mol$

Find the limiting reactant. Notice that stoichiometry of this reaction is 1 : 1, so we can compare moles directly. Moles of copper(II) acetate are lower than moles of sodium chromate, so copper(II) acetate is our limiting reactant.

Write the net ionic equation for this reaction:

$Cu^{2+} (aq) + CrO_4^{2-} (aq)\rightarrow CuCrO_4 (s)$

Notice that acetate is the ion spectator. This means it doesn't react, its moles throughout reaction stay the same. We started with:

$n_{(AcO)_2Cu} = 0.0053515 mol$

According to stoichiometry, 1 unit of copper(II) acetate has 2 units of acetate, so moles of acetate are equal to:

$n_{AcO^-} = 2\cdot 0.0053515 mol = 0.010703 mol$

The total volume of this solution doesn't change, so dividing moles of acetate by this volume will yield the molarity of acetate:

$c_{AcO^-} = \frac{0.010703 mol}{0.1500 L} = 0.0714 M$

8 0

3 years ago

200g of solution of magnesium

diamong [38]

The mass of reacted magnesium chloride is 23.75g, percent by mass of solution magnesium chloride is 90.9%.

<h3>What is the relation between mass & moles?</h3>

Relation between the mass and moles of any substance will be represented as:

n = W/M, where

W = given mass
M = molar mass

Moles of MgCl₂ = 200g / 95g/mol = 2.1mol

Moles of NaOH = 20g / 0.5mol

Given chemical reaction is:

MgCl₂ + 2NaOH → 2NaCl + Mg(OH)₂

From the stoichiometry of the reaction it is clear that

1 mole of MgCl₂ = reacts with 2 moles of NaOH
0.5 mole of NaOH = reacts with (1/2)(0.5)=0.25 moles of MgCl₂

Mass of reacted MgCl₂ = (0.25mol)(95g/mol) = 23.75g

Percent by mass of MgCl₂ in the given solution mixture will be calculated as:

% by mass = (Mass of MgCl₂ / Total mass of mixture) × 100%
Percent by mass of MgCl₂ = (200/200+20)×100% = 90.0&

In the above reaction we obtain NaCl as a solid, and MgCl₂ is the limiting reagent in it, from which 2 moles of NaCl is produced means

0.25 moles of MgCl₂ = produces 0.5 moles of NaCl

Mass of NaCl = (0.5mol)(58.5g/mol) = 29.25g

Hence, mass of reacted MgCl₂ is 23.75g, percent by mass of solution magnesium chloride is 90.9% and mass of the obtained solid is 29.25g.

To know more about mass & moles, visit the below link:

brainly.com/question/20838755

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8 0

1 year ago